Formula of the daily compound interest:
A = P.e^(r.t), where P is the initial investment, r = interest rate, t = number of years e= 2.718 and A = final amount
6,225.18= 4,543.11(e)^(r.15)
(e)^(r.15) = 6,225.18/4,543.11
(e)^(r.15) = 1.3702046
ln[(e)^(r.15)] = ln(1.3702046)
15.r = 0.314991
And r = 0.314491/15 = 0.020 OR 2%
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
In order to isolate k, we would first cross multiply
3*k=9*10
3k=90
Then to isolate k, we would divide both sides by 3 to get:
K=30
Hope this helps
Answer:
B
Step-by-step explanation:
n³-125=0
n³=125
n= ³√125
n=5
