Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
Answer:
10x
Step-by-step explanation:
Answer:
5995 hugs
Step-by-step explanation:
This is a combination problem: we want to make groups of two monkeys, where a pair of monkey 1 and 2 is the same pair of monkey 2 and 1 (it is the same hug). So, if the total number of monkeys at the zoo is 110, we have a combination of 110 choose 2:
C(110,2) = 110! / (2! * (110-2)!) = 110 * 109 / 2 = 5995
So the total number of hugs is 5995
The answer is cA cus Ca is the answer
