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meriva
3 years ago
6

What is the Greatest Common Factor of 30w and 70w ?

Mathematics
2 answers:
Tasya [4]3 years ago
6 0
The answer for this is 10
Alla [95]3 years ago
4 0
10w is the GCF of 30w and 70w
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Need help asap please !!
irinina [24]

Answer:

g(3) = 13

Step-by-step explanation:

The function g(3) means you replace every x value in the g(x) equation with 3:

g(x) = x^2 + 4\\g(3) = 3^2 + 4\\g(3) = 9 + 4\\g(3) = 13

Hope this helps!

7 0
2 years ago
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You are drawing two cards, without replacement, from a standard deck of 52 cards. What is the
Ket [755]
24% is the probity sorry just need points
6 0
3 years ago
Consider an isosceles trapezoid rotated about an axis of symmetry that passes through the midpoint of the bases. the minor base
Ronch [10]

Based on the calculation, the perimeter of the horizontal cross-section is equal to 36.13 cm.

<h3>How to calculate the perimeter?</h3>

In this scenario, the resulting geometrical shape formed when the cut is made at the middle of the height of the trapezoid and then rotated is a circle.

<u>Given the following data:</u>

  • Minor base = 10 cm.
  • Major base = 13 cm.

From the middle, the diameter of this circle is given by:

D = 1/2 (10 + 13)

D = 11.5 cm.

Now, we can calculate the perimeter:

Perimeter = πD

Perimeter = 3.142 × 11.5

Perimeter = 36.13 cm.

Read more on trapezoid here: brainly.com/question/4758162

#SPJ1

3 0
2 years ago
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
1 year ago
Suppose you buy a CD for $500 that earns 3% APR and is compounded quarterly. The CD matures in 3 years. Assume that if funds are
postnew [5]
The question is asking to choose among the following choices that states the early withdrawal fee of the account given in the problem, base on my calculation and further formulation about the said problem, I would say that the answer would be letter D. $3.75. I hope you are satisfied with my answer 
5 0
2 years ago
Read 2 more answers
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