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hram777 [196]
3 years ago
13

Compare 3 7/8 ___ 3 5/6

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

1 2/3 : 4 3/8 = 8

21

≅ 0.3809524

Step-by-step explanation:

Conversion a mixed number to a improper fraction: 1 2/3 = 1 · 3 + 2

3

= 5

3

Conversion a mixed number to a improper fraction: 4 3/8 = 4 · 8 + 3

8

= 35

8

Divide: 5

3

: 35

8

= 5

3

· 8

35

= 5 · 8

3 · 35

= 40

105

= 8

21


To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Which of the following situations can be represented by a proportional relationship?
Zina [86]

Answer:

i think D

Step-by-step explanation:

im not great at math but yea i think D

6 0
3 years ago
Read 2 more answers
Suppose that G(X) = F(x + 2). Which statement best compares the graph of
nignag [31]

Answer:

A

Step-by-step explanation:

If you have to add 2 to X to get it back to the original, it started out 2 to the left.  (It would seem like it ought to be C, but when you add an subtract from the x value in functions, it's opposite of what you might think.)

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3 years ago
The radiuses of two intersecting circles are 17 and 39. The distance between their centers is 44. Find the length of their commo
antoniya [11.8K]

Answer:

If x is the distance from centre fo the circle, with radius 25cm, to its intersection point with the common chord, x²+24²=25² =>x=7cm.

Distance from this intersecting point to the centre of the other circle=39–7=32cm

Ratio of the sides of the right triangle thus formed is 24:32=3:4. Since 3:4:5 is the basic pythagorean triplet, the radius of the other circle=5*24/3=40cm.

Aliter: radius of the other circle=√32²+24²= 40cm.

<h2><em>please</em><em> </em><em>mark</em><em> me</em><em> as</em><em> brainalist</em></h2>
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PLEASE ANSWER IT'S IN THE PICTURE I WILL MARK BRAINLIEST IF YOU'RE CORRECT!
harkovskaia [24]

Answer:

It is possible for a set of data values to have more than one mode. If there are two data values that occur most frequently, we say that the set of data values is bimodal. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

Step-by-step explanation:

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