Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
Germ-line mutations are mutations that would be passed down to future generations, and recombinations are where the information each parent passes down to the offspring is shuffled.
The genetic variation would have to come from random events: False
Only alternate generations would express any genetic variable: False
Body cell mutations would be the only source of heritable genetic variation: False
There would be no new heritable genetic variation possible in the population: True
