3.2s:8c
4.8s:12c
Therefore, you would need 4.8g of sugar to make 12 cakes. This was solved by using ratios.
A:
Ratio of all students in the class to girls is...
15:8
b:
Ratio of boys to girls....
7:8
Answer:
<em>(9,-5)</em>
Step-by-step explanation:
When you go down, the number will decrease. The vertical position is the Y axis. -3-2=5.
When you go right, the number will increase. The horizontal position is the X axis. 5+4=9
<em>(9,-5)</em>
<u>Hope this helps :-)</u>
7 1/4 + 5 3/5
First, you need a common denominator to add the two. 20 will work.
4x5=20, so we have to also multiply 1 by 5.
4x5=20, 1x5=5
5x4=20, so we have to also multiply 3 by 4.
5x4=20, 3x4=12
And now we put the fractions back in.
7 5/20 + 5 12/20
And add them.
7 5/20 + 5 12/20 = 12 17/20
Now, we're supposed to reduce it to its lowest form.
Unfortunately, the fraction cannot be reduced, because 17 is a prime number, meaning there are no factors to it except one and itself.
Therefore, the lowest form of 12 17/20 is 12 17/20
Your answer is B, 12 17/20
Answer:
The series is convergent answer ⇒ (a)
Step-by-step explanation:
* The series is -8/5 + 32/25 + -128/125 + ........
- It is a geometric series with:
- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5
* The difference between the convergent and divergent
in the geometric series is :
- If the geometric series is given by sum = a + a r + a r² + a r³ + ...
* Where a is the first term and r is the common ratio
* If |r| < 1 then the following geometric series converges to a / (1 - r).
- Where a/1 - r is the sum to infinity
* The proof is:
∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number
∴ r^n approach to zero
∴ S = a(1 - 0)/(1 - r) = a/(1 - r)
∴ S∞ = a/1 - r
* If |r| ≥ 1 then the above geometric series diverges
∵ r = -4/5
∴ IrI = 4/5
∴ IrI < 1
∴ The series is convergent
