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3 years ago

I need this asap, whats the answer??

Mathematics

2 answers:

Rudik [331]3 years ago

8 0

Answer:

$\large\boxed{x>\dfrac{9}{5}\to x>1\dfrac{4}{5}}$

Step-by-step explanation:

$\dfrac{2}{3}x-\dfrac{1}{5}>1\qquad\text{multiply both sides by LCD = 15}\\\\15\!\!\!\!\!\diagup^5\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-15\!\!\!\!\!\diagup^3\cdot\dfrac{1}{5\!\!\!\!\diagup_1}>(15)(1)\\\\(5)(2x)-(3)(1)>15\\\\10x-3>15\qquad\text{add 3 to both sides}\\\\10x>18\qquad\text{divide both sides by 10}\\\\x>\dfrac{18}{10}\\\\x>\dfrac{18:2}{10:2}\\\\x>\dfrac{9}{5}\to x>1\dfrac{4}{5}$

Norma-Jean [14]3 years ago

3 0

Answer: X>9/5

Step-by-step explanation:

Step 1: add 1/5 to both sides

2/3x -1/5+1/5>1+1/5

Step 2 :Simplify Your Answer to

2/3x>6/5

Step 3 :Multiply by both sides by 3

3*2/3x>6*3/5

Step 4: Simplify Your Answer To

2x>18/5

Step 5: divide by 2

2x/2 >18/5/2

Step 6 :Simplify your answer and u get

x>9/5

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Meldie made a cube whose side is (3x - 2) inches. Find its volume in cubic inches.

irinina [24]

Answer:

x^2(3x-2) cubic inches OR in^3

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

I AM UNAWARE IF YOU ASKED THAT ONE SIDE IS (3X-2) OR ALL. I WILL ANSWER BOTH PARTS

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NOTE: '^' MEANS TO THE POWER OF..

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Volume = v, abc = 3 sides of cube (height, width, length)

Using the formula for volume in a cube,

$v = abc$

We can solve this.

If one side is (3x-2)in,

(3x-2)(x)(x) = v.... x are the other two sides
x^2(3x-2) = v

x^2(3x-2) cubic inches OR in^3

If all sides are (3x-2)in,

Use the formula,

$(a - b) ^{3} = {a}^{3} + 3ab(b - a) - {b}^{3}$

We can solve this.

(3x-2)(3x-2)(3x-2) = v
(3x-2)^3 = v.... 3x = a and -2 = b
(3x)^3 + [(3)(3x)(2)][2-3x] - (2)^3 = v
27x^3 + 18x(2-3x) -8 = v
(27x^3 + 36x - 54x^2) - 8 = v.. Terms inside brackets - take 3x as common and leave out 8
3x(9x^2 -18x +12) = v... Take 3 as common again in the brackets
3x [ 3 ([3x^2 -6x] + 4) -8 = v....Take 3x common in the terms in square brackets
3x [ 3 [ 3x (x-2) + 4 ]] - 8 = v
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 = v

3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3

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If you have any questions regarding formulas or anything, comment and I will get back to you asap.

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5 0

1 year ago

Which value from the set (5,7,9,11,13) make inequality w-4<8 true?

ira [324]

Answer:

5,7,9,11

Step-by-step explanation:

8 0

3 years ago

Please help me with these

Alex Ar [27]

When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
$\lim_{x \to 0} (\frac{sinx}{x}) = 1$
$\lim_{x \to 0} (\frac{tanx}{x}) = 1$
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) $\lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}$

We can do this using the first and second method.
Method 1: Direct evaluation:

Substitute x = 0 to the function.
$\frac{\sqrt{0} - 5}{0 - 25}$
$= \frac{-5}{-25}$
$= \frac{1}{5}$

Method 2: Rearranging the function

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

$\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}$
$= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}$
$= \frac{1}{5}$

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.

8 0

3 years ago

Please help dont understand pleaseee

Zina [86]

Answer:

I think it is +2. I hope this helps.!

Step-by-step explanation:

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3 years ago

The number of professors in a college is p and the number of students is s, there are 16 times as many students as professors wr

Reika [66]