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3 years ago

13

The work for this math question

2 answers:

slega [8]3 years ago

5 0

First you need to move the decimal as many times to the right till it is a whole number then on the other number you need to do the same amount decimal moving then continue with long divison

Sedbober [7]3 years ago

5 0

The answer is 24.06. Hope this helps

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For what value of k, -4 is a zero of polynomial x2-x-(2k+2)?

bekas [8.4K]

Hmm
well, um
if -4 is a zero then if we subsitute -4 for x, we should get 0

so
0=(-4)²-(-4)-(2k+2)
0=16+4-2k-2
0=18-2k
2k=18
divide by 2
k=9

k=9
the value k is 9

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3 years ago

Find the solution of the system of equations.

irina1246 [14]

Answer:

x = -5 ; y= -1

Step-by-step explanation:

10y = -10

y = -1

-8x = 44 -4

-8x = 40

x = -5

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3 years ago

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luda_lava [24]

Answer:

1 square unit

Step-by-step explanation:

its easy

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3 years ago

The diagonals of a rhombus are 16 and 30. What is the perimeter

Varvara68 [4.7K]

The perimeter will be
.. P = 2√(16^2 +30^2) = 2*34 = 68

5 0

3 years ago

Read 2 more answers

In the diagram below,AB is the diameter of the circle with centre P.Point C lies on the y-axis.Given the coordinates of A and B

Step2247 [10]

Answer:

<em>The coordinates of P are (-2,0)</em>

<em>The radius of the circle is 5.</em>

Step-by-step explanation:

<u>Analytic geometry</u>

The diagram shows a circle with center P, and two points A(-6,3) and B(2,-3) that form the diameter of the circle.

a)

The center of the circle lies at the midpoint of A and B. The midpoint (xm,ym) can be calculated by:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

Substituting x1=-6, x2=2, y1=3, y2=-3:

$\displaystyle x_m=\frac{-6+2}{2}=\frac{-4}{2}=-2$

$\displaystyle y_m=\frac{3-3}{2}=0$

Thus, the coordinates of P are (-2,0)

b) The radius of the circle is the distance from the center to any point in its circumference. We can use the distance from P to A or B indistinctly.

Given two points A(x1,y1) and P(x2,y2), the distance between them is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substituting x1=-6, x2=-2, y1=3, y2=0:

$r=\sqrt{(-2+6)^2+(0-3)^2}$

$r=\sqrt{4^2+(-3)^2}$

$r=\sqrt{16+9}=\sqrt{25}=5$

The radius of the circle is 5.

4 0

3 years ago