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3 years ago

5. What number filter lens is recommended when welding with SMAW and using 1/8" (3.2 mm)

Engineering

1 answer:

Inessa05 [86]3 years ago

7 0

Answer:

What filter lens is recommended for SMAW?

Table of Filter Lenses for Protection From Radiant Energy

Type of Operation Electric Size 1/32 in. Arc Current (Amp)

Shield metal arc welding (SMAW) 3 to 5 60 to 160

5 to 8 160 to 250

More than 8 250 to 500

Explanation:

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A beam spans 25 feet and carries a uniformly distributed dead load equal to 0.6 klf (including beam self-weight) and a live load

jolli1 [7]

Answer:

A beam is a structural member that is subjected primarily to transverse loads and ... stress equal to σy, then the section Moment - Curvature (M-φ) response for .... Example 2.2 Design a simply supported beam subjected to uniformly distributed dead load of ... of the AISC manual, select W16 x 26 made from 50 ksi steel with.

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3 years ago

Hot air at an average temperature of 100 degC flows through a 3 m long tube with an inside diameter of 60 mm. The temperature of

Arte-miy333 [17]

Answer:

$\dot Q = 912.017\,W$

Explanation:

The heat transfer rate due to convection is calculated by this formula:

$\dot Q = h_{air}\cdot A_{tube, in}\cdot (T_{air} - T_{tube})$

The output is determined by replacing terms:

$\dot Q = (20.1\,\frac{W}{m^{2}\cdot ^{\textdegree}C})\cdot (\pi )\cdot (0.06\,m)\cdot (3\,m)\cdot (100^{\textdegree}C-20^{\textdegree}C)$

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3 years ago

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Convert the following indoor air quality standards, established by the U.S. Occupational Safety and Health Administration (OSHA)

sp2606 [1]

Wouldn’t this be science not engineering?

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3 years ago

Which wing shape controls lift and drag?

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Wing D (high camber and surface area, least weight) generated the most lift force and Wing C (most streamlined) generated the least drag force. It is concluded that the shape of a wing does affect the lift and drag of an airplane.

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2 years ago

A horizontal curve on a two-lane highway (10-ft lanes) is designed for 50 mi/h with a 6% superelevation. The central angle of th

fenix001 [56]

Answer:

The PT station is at 485+20.02 and 21.92 ft are to be cleared from the lane's shoulder to provide adequate stopping sight distance.

Explanation:

From table 3.5 of Traffic Engineering by Mannering

R_v=835

R=835+(10ft/2)= 840 ft.

Now T is given as

T=R tan(Δ/2)

Here Δ is the central angle of curve given as 35°

T=R tan(Δ/2)

T=840 x tan(35/2)

T=840 x tan(17.5)

T=264.85

Now

STA PC=482+72-(2+64.85)=480+07.15

Also L is given as

L=(π/180)RΔ

Here R is the radius calculated as 840 ft, Δ is the angle given as 35°.

L=(π/180)RΔ

L=(π/180)x840 x35

L=512.87 ft

STA PT=480+07.15+5+12.87=485+20.02

Now Ms is the minimum distance which is given as

$M_s=R_v(1-cos(\frac{90 \times SSD}{\pi Rv}))\\$

Here R_v is given as 835

SSD for 50 mi/hr is given as 425 ft from table 3.1 of Traffic Engineering by Mannering

So Ms is

$M_s=R_v(1-cos(\frac{90 \times SSD}{\pi Rv}))\\M_s=835(1-cos(\frac{90 \times 425}{\pi 835}))\\M_s=26.92 ft$

Now for the clearance from the inside lane

Ms=Ms-lane length

Ms=26.92-5= 21.92 ft.

So the PT station is at 485+20.02 and 21.92 ft are to be cleared from the lane's shoulder to provide adequate stopping sight distance.

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3 years ago