it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:
- It can make it difficult to interpret patterns and draw conclusions in a run chart.
- It can lead hinder the process, and make it unstable.
<h3>When a
data point falls outside the control limits of a run chart ?</h3>
If a data point falls is said to outside the control limits, we can say that the process is said to be out of one's control and it is good that an investigation is done to ascertain and remove the cause or causes.
So, it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:
- It can make it difficult to interpret patterns and draw conclusions in a run chart.
- It can lead hinder the process, and make it unstable.
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Answer: check the engines i swear if ur talking about an actual bike im gonna be so embarrassed lma0
Answer:
A: the condition of living without the benefit of education at some level
Explanation:
As a noun, ignorance is simply defined as the lack of knowledge about a common thing.
For example, he was ignorant about the schemes of his colleagues at the office.
Thus, from the given options, the correct answer is: "the condition of living without the benefit of education at some level".
Answer:
Driving test
Explanation:
Usually according to laws in countries worldwide, to be licenced to drive, one is required to go through a driving school to learn the ethics and rules of driving.
Answer:
The pressure upstream and downstream of a shock wave are related as
where,
= Specific Heat ratio of air
M = Mach number upstream
We know that 
Applying values we get
Similarly the temperature downstream is obtained by the relation
![\frac{T_{1}}{T_{o}}=\frac{[2\gamma M^{2}-(\gamma -1)][(\gamma -1)M^{2}+2]}{(\gamma +1)^{2}M^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B1%7D%7D%7BT_%7Bo%7D%7D%3D%5Cfrac%7B%5B2%5Cgamma%20M%5E%7B2%7D-%28%5Cgamma%20-1%29%5D%5B%28%5Cgamma%20-1%29M%5E%7B2%7D%2B2%5D%7D%7B%28%5Cgamma%20%2B1%29%5E%7B2%7DM%5E%7B2%7D%7D)
Applying values we get
![\frac{T_{1}}{423}=\frac{[2\times 1.4\times 1.8^{2}-(1.4-1)][(1.4-1)1.8^{2}+2]}{(1.4+1)^{2}\times 1.8^{2}}\\\\\therefore \frac{T_{1}}{423}=1.53\\\\\therefore T_{1}=647.85K=374.85^{o}C](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7B1%7D%7D%7B423%7D%3D%5Cfrac%7B%5B2%5Ctimes%201.4%5Ctimes%201.8%5E%7B2%7D-%281.4-1%29%5D%5B%281.4-1%291.8%5E%7B2%7D%2B2%5D%7D%7B%281.4%2B1%29%5E%7B2%7D%5Ctimes%201.8%5E%7B2%7D%7D%5C%5C%5C%5C%5Ctherefore%20%5Cfrac%7BT_%7B1%7D%7D%7B423%7D%3D1.53%5C%5C%5C%5C%5Ctherefore%20T_%7B1%7D%3D647.85K%3D374.85%5E%7Bo%7DC)
The Mach number downstream is obtained by the relation
