Write an equation of the circle with center (3,-2) and radius 6
1 answer:
Answer:
Step-by-step explanation:
We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.
Recall that the equation of a circle is given by:
Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (3, -2), <em>h</em> = 3 and <em>k</em> = -2. <em>r</em> = 6. Substitute:
Simplify:
In conclusion, the equation of the circle will be:
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Answer:
yes
Step-by-step explanation:
We are given that a Cauchy Euler's equation
where t is not equal to zero
We are given that two solutions of given Cauchy Euler's equation are t,t ln t
We have to find the solutions are independent or dependent.
To find the solutions are independent or dependent we use wronskain
If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.
Let
where t is not equal to zero.
Hence,the wronskian is not equal to zero .Therefore, the set of solutions is independent.
Hence, the set {t , tln t} form a fundamental set of solutions for given equation.
Answer:
Step-by-step explanation:
So, on substituting all these values, we get
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<h2>ADDITIONAL INFORMATION :-</h2>Sign of Trigonometric ratios in Quadrants
- sin (90°-θ) = cos θ
- cos (90°-θ) = sin θ
- tan (90°-θ) = cot θ
- csc (90°-θ) = sec θ
- sec (90°-θ) = csc θ
- cot (90°-θ) = tan θ
- sin (90°+θ) = cos θ
- cos (90°+θ) = -sin θ
- tan (90°+θ) = -cot θ
- csc (90°+θ) = sec θ
- sec (90°+θ) = -csc θ
- cot (90°+θ) = -tan θ
- sin (180°-θ) = sin θ
- cos (180°-θ) = -cos θ
- tan (180°-θ) = -tan θ
- csc (180°-θ) = csc θ
- sec (180°-θ) = -sec θ
- cot (180°-θ) = -cot θ
- sin (180°+θ) = -sin θ
- cos (180°+θ) = -cos θ
- tan (180°+θ) = tan θ
- csc (180°+θ) = -csc θ
- sec (180°+θ) = -sec θ
- cot (180°+θ) = cot θ
- sin (270°-θ) = -cos θ
- cos (270°-θ) = -sin θ
- tan (270°-θ) = cot θ
- csc (270°-θ) = -sec θ
- sec (270°-θ) = -csc θ
- cot (270°-θ) = tan θ
- sin (270°+θ) = -cos θ
- cos (270°+θ) = sin θ
- tan (270°+θ) = -cot θ
- csc (270°+θ) = -sec θ
- sec (270°+θ) = cos θ
- cot (270°+θ) = -tan θ