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djverab [1.8K]
2 years ago
15

Write an equation of the circle with center (3,-2) and radius 6

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

Answer:

\displaystyle (x-3)^2 + (y+2)^2 = 36

Step-by-step explanation:

We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.

Recall that the equation of a circle is given by:

\displaystyle (x-h)^2 + (y-k)^2 = r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (3, -2), <em>h</em> = 3 and <em>k</em> = -2. <em>r</em> = 6. Substitute:

\displaystyle (x-(3))^2  +(y-(-2))^2 = (6)^2

Simplify:

\displaystyle (x-3)^2 + (y+2)^2 = 36

In conclusion, the equation of the circle will be:

\displaystyle (x-3)^2 + (y+2)^2 = 36

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