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blagie [28]
2 years ago
9

What is 6.38 to 1 decimal place​

Mathematics
1 answer:
agasfer [191]2 years ago
7 0

Answer: Is 6.4

Step-by-step explanation: I hope I helped in some way shape or form.

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2. State the domain for the following ordered pairs: { (4, -2), (6, -7), (4, 3), (-8, 1), (-3, 5) } *
Fofino [41]

Answer:

(4,6,4,-8,-3)

Step-by-step explanation:

Domain means of function is the set of all possible inputs for function

4 0
3 years ago
PLEASE HELP I NEED HELP 10 POINTS
mestny [16]

Answer:

A kite with a 100 foot-long string is caught in a tree. When the full length of the string is stretched in a straight line to the ground, it touches the ground a distance of 30 feet from the bottom of the tree. Find the measure of the angle between the kite string and the ground.

17°

27°

63°

73°Step-by-step explanation:

8 0
3 years ago
a line in the standard (x,y) coordinate plane contains the points M(-2,4) and N(8,10) What is the midpoint of MN
Ivahew [28]

Answer:

(3, 7)

Step-by-step explanation:

The midpoint of a line joining the points  (x1, y1) and (x2, y2) has midpoint

[(x1 + x2)/ 2]. (y1 + y2)/2 ]

Substituting the given points:-

Midpoint of MN =  (-2 + 8)/2 ,  (4 + 10)/2

= 6/2 , 14/2

= (3, 7)   (answer)

3 0
4 years ago
What is the 15th term of the sequence A(n) = 50 - 3(n-1) ?
Alexus [3.1K]

Answer:

A(15)=8

Step-by-step explanation:

Given that,

A(n)=50 - 3(n-1)

We need to find the 15th term of the sequence. Put n = 15 in the above sequence so that,

A(15)=50 - 3(15-1)\\\\A(15)=50-3(14)\\\\A(15)=50-42\\\\A(15)=8

So, the 15th term of the sequence is 8.

7 0
3 years ago
Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
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