Simplifying h(x) gives
h(x) = (x² - 3x - 4) / (x + 2)
h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)
h(x) = ((x + 2)² - 7x - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)
h(x) = (x + 2) - 7 - 22/(x + 2)
h(x) = x - 5 - 22/(x + 2)
An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.
My guess would be x = -30
Answer:
D. 81
Step-by-step explanation:
Raise
3
to the power of
4
.
81
=
x
Rewrite the equation as
x
=
81
.
x
=
81
Answer:
Step-by-step explanation:
This is an order of operations question. First in PEMDOS you want to do your parenthesis, turn (5-2) into 3,
15 ÷ 3 + 4
Then do your divison, turning 15 ÷ 3 into 5
5 + 4
Then finish with 5 + 4
The answer is 9