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s344n2d4d5 [400]
2 years ago
14

Hep help help help hell

Mathematics
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

\frac{2x + 4}{2}  < 6 \\ 2x + 4 < 2 \times 6 \\ 2x + 4 < 12 \\ 2x < 12 - 4 \\ 2x < 8 \\ x <  \frac{8}{2}  \\  \color{blue} \boxed{x < 4}

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.002 is 1/10 of what
amid [387]
Let the unknown number be x.  Then (1/10)x = 0.002.  To solve for x, multiply both sides by 1000 to remove the decimal fraction 0.002.

Then 1000(1/10)x = 1000(0.002), or 100x = 2.  Dividing both sides by x returns 

x=100/2, or x= 50 (answer)
5 0
3 years ago
How to find the discounted price example $25.00 is the original price and the discount is 15%
Alexandra [31]
Since the price is now 15% less you would first find what 15% of 25 is  by using 25*.15 and get 3.25  then you subtract that from 25 and get 25-3.25=                     $21.75
3 0
3 years ago
Rectangle PQRS with vertices P(- 6, 9) , Q(3, 6); R(0, - 9) and S(- 9, - 6)
STatiana [176]

Answer:

multiply the original coordinate by 3 so its c

Step-by-step explanation:

multiply the original coordinate by 3

6 0
3 years ago
Can someone help me I’ll Mark brainliest I been struggling with this one :(
mariarad [96]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as
posledela

Answer:(a) margin error = 2.4%

(b) The margin error gives the measure in percentage of how the population parameter determined differ from the real population statistics or value.

(c) in 90% of the samples of teens in the country, the percent who go online several times a day will be within 50.6% and 55.4%. of the estimated 100%

Step-by-step explanation:

Using the proportion formulae

Margin error = z √p(1-p)/n

n= 1170, p = 53% = 0.53, 1-p = 0.47

and the z value at 90% C.I = 1.645

M error= 1.645 √0.53×0.47/1170

Margin error = 0.024 = 0.024 ×100

Margin error = 2.4%

53 - 2.4 = 50.6% and 53 + 2.4 = 55.4%

In other words 90% of the time: the number of teens who go online several time a day will be between 50.6 and 55.4%.

8 0
3 years ago
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