15 points please help

The population of a bacteria colony is growing exponentially, doubling every 6 hours. If there are 150 bacteria currently presen

marusya05 [52]

Answer:

If rounded to the nearest 10 bacteria, then it would be 500 bacteria.

Step-by-step explanation:

First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.

8 0

3 years ago

Expand, and simplify the following expressions a. (2x+y)(x+y) + (2x-y)(x+y)

tankabanditka [31]

Step-by-step explanation:

2x²+2xy+yx+y²+2x²+2xy-yx+y²

2x²+2x²+2xy+2xy+yx-yx+y²+y²

2x²+2x²+2xy+2xy

4x²+4xy

7 0

3 years ago

Read 2 more answers

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

Roland’s Boat Tours sells deluxe and economy seats for each tour it conducts. In order to complete a tour, at least 1 economy se

vovangra [49]

Roland’s Boat Tours will make more money if they sell more economy seats, hence the maximum profit is attained if they only sell the minimum deluxe seat which is 6

6*35+ 24*40 = 210+960= $1170

Given details

To make a complete tour, at least 1 economy seats

and 6 deluxe seats

Maximum passengers per tour = 30

"Boat Tours makes $40 profit for each economy seat sold and $35 profit for each deluxe seat sold"

Therefore, to maximise profit, he needs to take more of economy seats

Hence

Let a deluxe seat be x and economy seat be y

Maximise

6 x+ 24y = 30

The maximum profit from one tour is = 6*35+ 24*40 = 210+960= $1170

Learn more

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7 0

2 years ago

What is the vertical asymptote of the function? O x=-10 O x=-2 O x = 0 Ox=2

Alexxx [7]

Answer:d

Step-by-step explanation:

3 0

3 years ago