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zaharov [31]
3 years ago
15

Here are two expressions whose sum is a new expression, A.

Mathematics
1 answer:
mash [69]3 years ago
6 0

Answer:

All the points except A and C would be valid.

Step-by-step explanation:

This is because A and C are both negative whole numbers therefore they are not polynomials.

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Given: F(x) = 5x - 6 and G(x) = x - 4
fomenos

Answer:

Correct choice is \dfrac{x+26}{5}

Step-by-step explanation:

1. If F(x)=5x-6, then you can find the inverse F^{-1}(x):

y=5x-6,\\ \\5x=y+6,\\ \\x=\dfrac{y+6}{5},\\ \\F^{-1}(x)=\dfrac{x+6}{5}.

2. If G(x)=x-4, then

y=x-4,\\ \\x=y+4,\\ \\G^{-1}(x)=x+4.

3. Hence,

G^{-1}(F^{-1}(x))=G^{-1}\left(\dfrac{x+6}{5}\right)=\dfrac{x+6}{5}+4=\dfrac{x+26}{5}.

7 0
4 years ago
si tienes una mesa de 25m de largo por 10 de ancho ¿ en cuanto varíaran cada una de sus dimensiones para que sin alterar su supe
Murrr4er [49]

responder: 8,75

Cada dimensión será de 8,75 porque si la longitud es de 25 m de largo y el ancho es 10, si los sumamos y obtendremos 35. Así que 35 dividido entre 4 es 8,75

5 0
3 years ago
Just some questions I need answered!
Anni [7]

4z>-60

divideby 4

z>-15


x+19 <=-5

subtract 19 from each side

x<= -24


7 0
3 years ago
If a study determines the difference in average salary for subpopulations of mechanical engineers and civil engineers is NOT sig
uysha [10]

Both are not earning different salaries.

If a study determines the difference in average salary for subpopulations of mechanical engineers and civil engineers is NOT significant, then the subpopulations of mechanical and civil engineers are not earning different salaries.
Study determines that there is not any significant study so thats why both are not earning.


Learn more about average median on:

brainly.com/question/14532771

#SPJ10

3 0
2 years ago
If y = -6cosx, what is the amplitude?
aniked [119]

 

\displaystyle\bf\\y=-6cos\,x\\\\\textbf{is equivalent to:}\\\\y=6cos(x+\pi)\\\\\textbf{where 6 is the maximum value or amplitude}\\\\\implies~~~\boxed{\bf~amplitude=6}

 

8 0
3 years ago
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