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11Alexandr11 [23.1K]
2 years ago
8

During region C of the graph above the energy being absorbed is a. increasing the velocity of the water particles. b. increasing

the distance between the water particles and reducing their phase energy. c. increasing the distance between the water particles and increasing their phase energy. d. decreasing the velocity of the water particles.
Chemistry
1 answer:
Mkey [24]2 years ago
7 0

Answer:

Your answer would be B. Increasing the distance between the water molecules and increasing their phase energy.

Explanation:

Hope this helps you answer this question!

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one kilogram of water (V1 = 1003 cm^3*kg-1) in a piston cylinder device at (25°C) and 1 bar is compressed in a mechanically reve
vova2212 [387]

Answer:

Q = -18118.5KJ

W = -18118.5KJ

∆U = 0

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Explanation:

W = RTln(P1/P2)

P1 = 1bar = 100KN/m^2, P2 = 1500bar = 1500×100 = 150000KN/m^2, T = 23°C = 23 + 273K = 298K

W = 8.314×298ln(100/150000) = 8.314×298×-7.313 = -18118.5KJ ( work is negative because the isothermal process involves compression)

∆U = Cv(T2 - T1)

For an isothermal process, temperature is constant, so T2 = T1

∆U = Cv(T1 - T1) = Cv × 0 = 0

Q = ∆U + W = 0 + (-18118.5) = 0 - 18118.5 = -18118.5KJ

∆H = Cp(T2 - T1)

T2 = T1

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∆S = Q/T

Mass of water = 1kg

Heat transferred (Q) per kilogram of water = -18118.5KJ/Kg

∆S = (-18118.5KJ/Kg)/298K = -60.80KJ/KgK

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What causes these H-bonds to form?
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