D = m / V
D = 2790 g / 205 mL
D = 13.60 g/mL
Answer:
Y = 62.5%
Explanation:
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In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

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Answer:
23.2 g of Al will be left over when the reaction is complete
Explanation:
2Al + 3S → Al₂S₃
1 mol of Al = 26.98 g
1 mol of S = 32.06 g
Mole = Mass / Molar mass
63.8 g/ 26.98 g/m = 2.36 mole of Al
72.3 g / 32.06 g/m = 2.25 mole of S
2 mole of Aluminun react with 3 mole of sulfur
2.36 mole of Al react with (2.36 .3)/2 = 3.54 m of S
As I have 2.25 mole of S, and I need 3.54 S, is my limiting reagent so the limiting in excess is the Al.
3 mole of S react with 2 mole of Al
2.25 mole of S react with (2.25 m . 2)/3 = 1.50 mole
I need 1.50 mole of Al and I have 2.36, that's why the Al is in excess.
2.36 mole of Al - 1.50 mole of Al = 0.86 mole
This is the quantity of Al without reaction.
Molar mass . mole = Mass → 26.98 g/m . 0.86 m = 23.2 g
<u>Answer:</u> The average speed of the runner is 6.618 miles/hr
<u>Explanation:</u>
Average speed is defined as the ratio of total distance traveled to the total time taken.
To calculate the average speed of the runner, we use the equation:

We are given:
Distance traveled = 4339 ft
Time taken = 7.45 mins
Putting values in above equation, we get:

To convert the speed into miles per hour, we use the conversion factors:
1 mile = 5280 ft
1 hr = 60 mins
Converting the speed into miles per hour, we get:

Hence, the average speed of the runner is 6.618 miles/hr
Answer:

Explanation:
Moles of SO₃ = 0.760 mol
Volume = 1.50 L


[SO₃] = 0.5067 M
Considering the ICE table for the equilibrium as:

Given:
Equilibrium concentration of O₂ = 0.130 mol
Volume = 1.50 L


[O₂] = x = 0.0867 M
[SO₂] = 2x = 0.1733 M
[SO₃] = 0.5067-2x = 0.3334 M
The expression for the equilibrium constant is:
