The angle = 67<span>° and the pole is a right-angled triangle. Therefore the distance required to find (say "x) is the angle opposite the right-angle. The following equation needs to be solved:
cos 67 = 137 / x
Solving for x;
x = 350.62 ft</span>
Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40.
From there use algebraic steps to find out what x is ( the break - even point ).
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40
0.855625x - 4x + 20 = 1.265625x + 6x + 40
-0.41x - 4x + 20 = 6x + 40
-4.41x + 20 = 6x + 40
20 = 10.41x + 40
-20 = 10.41x
-1.92122958694 = x
Rounded to the nearest tenth it's -1.9 = x.
Tell me if I got something wrong :)
What question is that from? I'm talking about ur grade
Step-by-step explanation:
these are the functions
and the others are not a functions because the domain can't match to more than one
Answer:
v=9
Step-by-step explanation:
