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White raven [17]
3 years ago
13

Will give brainliest for correct answer

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:

1. A+B>C

2. B+C>A

3. A+C>B

Thus given two sides of A=9 and B=12 C can be:

12−9<C<12+9

C range 5<C<11

Hope this helps you!

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3 years ago
Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°
Iteru [2.4K]

Answer:

The answer to your question is: the first option  - 9/ \sqrt{80}

Step-by-step explanation:

Process

          cosФ = adjacent side / hypotenuse

          -1/9 = adjacent side / hypotenuse

          adjacent side = -1    hypotenuse = 9

          c² = a² + b²

          b² = c² - a²

           b² = 81 - 1

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But b is negative because we are in the third quadrant.

          b = -\sqrt{80}

Finally   csc Ф = hypotenuse / opposite side

             csc Ф = - 9 / \sqrt{80}

4 0
3 years ago
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