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3 years ago

35% of f is 14. What is f

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer: 40

Step-by-step explanation:

* Hopefully the work below helps:) Mark me the brainliest:)!!

∞ 234483279c20∞

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You invest $2000 in an account that pays 2.7% interest compunded annually. If you make no payments into the account, what will t

vaieri [72.5K]

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Annually: 2,610.56

Monthly: 2,619.13

Step-by-step explanation:

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3 years ago

What is the area for a circle

nignag [31]

Answer:

Area for a circle is

Step-by-step explanation:

=pi*r^2

=22/7*r^2

#Hope it helps uh

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3 years ago

Read 2 more answers

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

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3 years ago

Which expression is equivalent to (8x – 20) + (-4x + 12)?

lana66690 [7]

Answer:

B. 4x-8

Step-by-step explanation:

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3 years ago

Rename the value of $780,000

ANEK [815]

Seven hundred and and eighty thousand

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3 years ago