Answer:
=3–√−13–√+1⋅3–√−13–√−1
=(3–√−1)23–√2−12
=3–√2+12−23–√3−1
=4−23–√2
2−13–√
a=2,b=−1.
Step-by-step explanation:
Answer:
Step-by-step explanation:
The rate if increase of side of square is 7cm/s
dL/dt=7
At what area is the area increasing
dA/dt=?
Areas of square is give to be 36cm²
Analysis
Let L be the length of each side of the square, a square has equal side.
Area of square is give as L²
Area=L²
L²=36
i.e L=√36
L=6cm
Therefore at t=0 L=6cm and A=36cm²
A=L²
dA/dL=2L
Given that, dL/dt=7
Multiply the two differential together
dA/dt= dA/dL × dL/dt
dA/dt= 2L × 7
dA/dt= 2×6×7
dA/dt= 84cm²/s
The rate of increase of the square is 84cm²/s
Answer: 7x^2-8x+10
Step-by-step explanation: hope this helps gl :)
thx for the points
Answer:
(
4
,−
13
)
Step-by-step explanation:
The answer you are looking for is B. False. <span>The zero between the other numbers counts.</span>
