Please help ASAP!!!!<br><br> Which type of transformation is shown ?

John is building a stage for a school play.The stage is 151/2 feet long and 20 feet wide. Select all options that represents the

Sergeeva-Olga [200]

C and E. hope this helps!

5 0

3 years ago

Read 2 more answers

Which property is shown? 2.3 + (-1.2 + 9.6) = (2.3+ (-1.2)) + 9.6

abruzzese [7]

Answer:

Associative property of addition

Step-by-step explanation:

A change of grouping is the associative property of addition.

6 0

4 years ago

In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38

Ganezh [65]

Answer:

a

$0.716 < p < 0.744$

b

$0.3498 < p < 0.4089$

c

With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at b

Step-by-step explanation:

From the question we are told that

The sample size is $n = 1003$

The number that complained about dirty or ill-equipped bathrooms is $e = 732$

The number that complained about loud or distracting diners at other tables is $q = 381$

Given that the the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100- 95)\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the value is

$Z_{\frac{\alpha }{2} } = 1.96$

Considering question a

The sample proportion is mathematically represented as

$\r p = \frac{e}{n}$

=> $\r p = \frac{732}{1003}$

=> $\r p = 0.73$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p (1- \r p)}{n} }$

$E = 1.96* \sqrt{ \frac{ 0.73 (1- 0.73)}{1003} }$

$E = 0.01402$

The 95% confidence interval is

$\r p - E < p < \r p +E$

$0.73 - 0.01402 < p < 0.73 + 0.01402$

$0.716 < p < 0.744$

Considering question b

The sample proportion is mathematically represented as

$\r p = \frac{q}{n}$

=> $\r p = \frac{381}{1003}$

=> $\r p = 0.3799$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p (1- \r p)}{n} }$

$E = 1.96* \sqrt{ \frac{ 0.3799 (1- 0.3799)}{1003} }$

$E = 0.0300$

The 95% confidence interval is

$\r p - E < p < \r p +E$

$0.3798 - 0.0300 < p < 0.3798 + 0.0300$

$0.3498 < p < 0.4089$

8 0

3 years ago

Help me please this is my last question

ohaa [14]

8= 2 liters of punch
16= 4 liters of punch
20= 5 liters of punch
28= 7 liters of punch

5 0

3 years ago

Santiago receives $179

Mashutka [201]

9514 1404 393

Answer:

$400 at 2%
$900 at 3%
$3600 at 4%

Step-by-step explanation:

Let x represent the amount invested at 3%. Then (x -500) is the amount invested at 2%, and 4x is the amount invested at 4%. The total interest income is ...

0.02(x -500) + 0.03x + 0.04(4x) = 179

0.21x -10 = 179 . . . . . simplify

0.21x = 189 . . . . . . . . add 10

x = 900 . . . . . . . . . . . divide by 0.21

x -500 = 400

4x = 3600

$400 is invested at 2%; $900 is invested at 3%, $3600 is invested at 4%.

3 0

3 years ago

Please help ASAP!!!! Which type of transformation is shown ?