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Readme [11.4K]
2 years ago
5

1. What is the positive solution to this equation? 6x2 - 18x = 24

Mathematics
1 answer:
Orlov [11]2 years ago
8 0

Answer:

x = -4

Step-by-step explanation:

Lets work on this :D

(6x × 2) - 18x = 24

=>12x - 18x = 24

=> -6x = 24

=> x = -4

Please give me brainliest if this helped! :D

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The larger of two numbers is 4 more than 2 times the smaller number. If the sum of the two numbers is 28, what is the larger num
Musya8 [376]

Answer:

The larger number is 20.

Step-by-step explanation:

Let x and y be the two numbers.

y = 2x + 4

x + y = 28

So x + 2x + 4 = 28

3x = 24

x = 8

y = 20

3 0
2 years ago
Find the shaded region.
pashok25 [27]

Answer:

Step-by-step explanation:

let the side of outer square=2x

then x²+x²=(20√2)²

2x²=800

x²=400

x=√400=20 in

2x=2×20=40 in

area of outer square=40²=1600 in²

area of inner square=(20√2)²=800 in²

area of shaded  region A=1600-800=800 in²

8 0
3 years ago
Factor completely
svet-max [94.6K]

Answer:

B.) 2(5x-4)(x+1)

Step-by-step explanation:

10x^2+2x-8

= 2(5x^2 + x - 4)

= 2(5x^2 + 5x - 4x - 4)

= 2[5x(x + 1) - 4(x + 1)]

= 2(5x-4)(x+1)

8 0
3 years ago
Read 2 more answers
Due 4/29/22. add explanation to please if you can, so that i can understand better
vagabundo [1.1K]

Answer:

48

240 ÷ 5 = 48

Please Mark Brainliest If This Helped!

8 0
2 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
2 years ago
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