2 years ago

1. What is the positive solution to this equation? 6x2 - 18x = 24

Mathematics

1 answer:

Orlov [11]2 years ago

8 0

Answer:

x = -4

Step-by-step explanation:

Lets work on this :D

(6x × 2) - 18x = 24

=>12x - 18x = 24

=> -6x = 24

=> x = -4

Please give me brainliest if this helped! :D

You might be interested in

A pyramid has a square base with sides 8" and a slant height of 5". total area =

Vinil7 [7]

The answer is 224 sq units

6 0

3 years ago

Read 2 more answers

Bob and ling are playing a number pattern game. Bob wrote the following sequence

seraphim [82]

The unknown term is 22.6

28.9
26.8
24.7
22.6
20.5

As you can see, the numbers after the decimal point descends by 1 point. 9 , 8 , 7 , 6 , 5
While the numbers before the decimal point descends by 2 points, 28 , 26 , 24 , 22 , 20

6 0

2 years ago

Read 2 more answers

Solve the equation. у+ 3 = -у +9 y=1 y= 3 y= 6 y= 9

Anna007 [38]

The first y equals -3 and the second y equals -9

8 0

2 years ago

YO PLEASE HELP N ONLY ANSWER IF U KNOW THE ANSWER!!

Ronch [10]

HOPE THIS HELPS YOU..... :)

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago