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egoroff_w [7]
2 years ago
9

What make up molecules

Chemistry
2 answers:
AfilCa [17]2 years ago
7 0

Answer:

atom

Explanation:

because the definition of molecule is the group of an atom is called molecule

enyata [817]2 years ago
5 0

Answer:

Molecules are made up of One Or More atoms.If they contain More than One atom,the atom can be the Same Or different.

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Can you guys help me I really need help ! Just started this 6th grade I really need help I’m use to this
NeX [460]

Answer:

Mechanical - Freezing & Thawing, Acid Rain, Flowing Water, oxidation

Chemical - Rusting, abrasion

Explanation:

hope this helps!

5 0
3 years ago
According to the equation for this chemical reaction, what does the 2 in front of 2Ag tell us?
storchak [24]
The number of molecules involved in the reaction, in this case, the number of Ag atoms involved.
3 0
4 years ago
Read 2 more answers
If I have 9 moles of a gas at a pressure of 8.7 atm and a volume of 18 liters, what is the temperature?
alukav5142 [94]
212K
pV=nRT.
R = 0.08206
5 0
4 years ago
What is the ionic compound formula sodium nitride?​
Leona [35]

Answer:

In ionic compounds, the charges of constituent ions must balance. This can be achieved by having three sodium ions per nitride ion. Therefore, the formula of sodium nitride is Na3N

Explanation:

7 0
3 years ago
Read 2 more answers
Determine the concentration of nh3(aq) that is required to dissolve 743 mg of agcl(s) in 100.0 ml of solution. the ksp of agcl i
AnnyKZ [126]

Answer:

1.1 M

Explanation:

The dissociation of AgCl_{(s)} is as follows:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Given Value for K_{sp} = 1.77*10^{-10}

The equation for the reaction for the formation of complex ion Ag(NH_3)^+_2 is :

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

The value of K_f = 1.6*10^7

If we combine both equation and find the overall equilibrium constant will be:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

<u>                                                                                                      </u>

AgCl_{(s)}+2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

                                 K = (1.77*10^{-10})(1.6*10^7)

                                  K = 0.00283

If [NH_3] = x M

The solubility of  AgCl_{(s)} in the NH_3 solution will be:

x = 743*10^{-3}g * \frac{mol AgCl}{143.32g}*\frac{1}{0.1000L}

x = 0.0518 M

Constructing an ICE Table; we have :

                             AgCl_{(s)} + 2 NH_3{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

Initial  (M)                                     x                   0                      0

Change  (M)                       -2 (0.0518)      + 0.0518          + 0.0518

Equilibrium (M)                    x - 0.1156          0.0518             0.0518

Equilibrium constant;

(K) = \frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}

0.00283 = \frac{(0.0518)^2}{(x-0.1156)^2}

0.00283 = (\frac{0.0518}{x-0.1156})^2

x = 0.1156 + \sqrt{\frac{0.0518^2}{0.00283} }

x = [NH₃] =  1.089 M

[NH₃] ≅ 1.1 M                

8 0
3 years ago
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