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Margaret [11]
3 years ago
13

In 1906, a 600 g diamond was found at the Premier Mine in South Africa- the world's largest uncut diamond. Suppose the diamond's

temperature changed by 2℃ as it was cut. If the specific heat capacity of diamond is 710 J/g℃, how much energy was transferred to the diamond by the heat?
Chemistry
1 answer:
lys-0071 [83]3 years ago
5 0

Answer:

852000 J

Explanation:

The following data were obtained from the question:

Mass (M) = 600 g

Change in temperature (ΔT) = 2 °C

Specific heat capacity (C) = 710 J/g℃

Heat transfered (Q) =?

Thus, we can obtain the the heat transfered to the diamond by using the following formula:

Q = MCΔT

Q = 600 × 710 × 2

Q = 852000 J

Therefore, the energy transfered to the diamond by heat is 852000 J

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One gallon of water has a mass of 3.78kg. Water is 11.2% hydrogen by mass. Calculate the mass of hydrogen contained in this gall
olchik [2.2K]

Answer:

A model is developed for predicting oxygen uptake, muscle blood flow, and blood chemistry changes under exercise conditions. In this model, the working muscle mass system is analyzed. The conservation of matter principle is applied to the oxygen in a unit mass of working muscle under transient exercise conditions. This principle is used to relate the inflow of oxygen carried with the blood to the outflow carried with blood, the rate of change of oxygen stored in the muscle myoglobin, and the uptake by the muscle. Standard blood chemistry relations are incorporated to evaluate venous levels of oxygen, pH, and carbon dioxide.

Explanation:

8 0
3 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

7 0
3 years ago
I will give brainlyst for this so pls help
omeli [17]

Answer:

Answer -b

Explanation:

Brainliest pls

8 0
3 years ago
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This part insulates the reaction chamber from the transfer of heat to or from the surrounding environment. this part contains a
Masja [62]

The amount of heat transferred in and out of the system is measured by calorimetry. The thermometer in the calorimeter is used to measure the temperature.

<h3>What are the parts of the calorimetry device?</h3>

The thermometer (A) is a device used to measure the final and the initial temperature of the water or any other liquid in a system. A metal vessel is a place where the reaction mixture is present.

In-vessel (B), water, and metal are placed before the beginning of the experiment. The styrofoam cup or the outer metal vessel (C) insulates the instrument, from regulating the heat transformation.

Therefore, part A measures the temperature of the reaction mixture.

Learn more about insulated containers here:

brainly.com/question/866735

3 0
2 years ago
127) Thirty-six colonies grew in nutrient agar from 1.0 ml of undiluted sample in a standard plate count. How many cells were in
SIZIF [17.4K]

Answer:

36

Explanation:

Since the sample was undiluted the number of colonies is the number that grew on the nutrient agar which is 36 colonies. If it was diluted for example let say 0.1 ml from a dilution in which 1 ml of the sample was added to 9 ml of water, and it grew  colonies then  0.1 ml  yielded  6 colonies, 1 ml of the diluted sample will yield 60 colonies and 10 ml will have 600 colonies and therefore the 1 ml undiluted sample will have 600 colonies.

6 0
3 years ago
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