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DerKrebs [107]
3 years ago
15

Stems are important plant structures because they _________.

Chemistry
1 answer:
12345 [234]3 years ago
3 0

Answer:

D

Explanation:

supports the plant,leaves and flowers

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A chemist wants to observe the following reaction:
stiv31 [10]

It take more energy to break the bonds of the reactants and less energy is given off when the product bonds are formed.

<h3>What is Energy?</h3>

Energy is defined as the ability to do work. Work is done in the breaking or formation of bonds.

The standard Enthalpy (ΔH) of water which was formed in the given reaction is negative.

ΔH= Δproduct - Δreactant

This means that the energy to break the bonds of the reactants is more.

Read more about Enthalpy here brainly.com/question/14291557

3 0
2 years ago
2. If you are given the mass of a reactant in grams and want to calculate the mass of
Darina [25.2K]

Answer:

1. Convert given mass of reactant to moles.

2. Convert moles of reactant to moles of product using the coefficients in the balanced equation.

3. Convert moles of product back to grams of product

Explanation:

In order to find out the mass of a given product in grams you would have to convert the grams into moles by multiplying 1 mole over the given mass of the reactant. Then, you would convert the moles of the reactant into moles of the product using mole ratio. And lastly, you would multiply by the mass of the product to calculate the mass back to grams.

Hope this helps!!<3

6 0
3 years ago
Which of the following best decribes the fluoride content of bottled water? unpredictable, high, low, moderate
Anton [14]
The fluoride content of bottled water is unpredictable.  
8 0
3 years ago
()
const2013 [10]

Answer:

\large \boxed{\text{-1276 kJ/mol}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                             CH₃CH₂OH        +  3O₂ ⟶ 2CO₂ + 3H₂O

Bonds:         5C-H 1C-C 1C-O 1O-H    3O=O     4C=O   6O-H

D/kJ·mol⁻¹:    413    347  358  467       495        799      467

\Delta H = \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\\sum{D_{\text{reactants}}} = 5 \times 413 + 1 \times 347 + 1 \times 358 + 1 \times 467 + 3 \times 495 = 3237 + 1485\\=\text{4722 kJ}\\\sum{D_{\text{products}}} = 4 \times 799 + 6 \times 467 =3196 + 2802 = \text{5998 kJ}\\\Delta H = 4722 - 5998= \textbf{-1276 kJ} \\ \text{The overall energy change is $\large \boxed{\textbf{-1276 kJ/mol}}$}.

6 0
4 years ago
An experiment illustrating fizzy drink production
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That is a alkazeltser shot
3 0
2 years ago
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