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nekit [7.7K]
2 years ago
5

Help me please an thank you

Chemistry
1 answer:
miskamm [114]2 years ago
6 0

Molecular formula

hope that helps^^

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Acellus<br> How many grams of strontium<br> (Sr, 87.62 g/mol) are in 2.92<br> moles of strontium?
saul85 [17]

Answer:

There are 255, 85 grams of Strontium in 2,92 moles.

Explanation:

We perform a simple rule of three to calculate the number of grams, knowing that one mole of Sr weights 87, 62 grams:

1 mol Sr---------87, 62 grams

2,92 mol Sr-----x=(2,92 mol Sr x-87, 62 grams)/1 mol Sr= 255,8504 grams

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3 years ago
How do we find mass number of elements in chemistry ?​
sukhopar [10]

Answer: Atomic number, atomic mass, and relative atomic mass

Explanation:

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3 years ago
1. Classify rust:
Arisa [49]
1. Rust, or Fe2O3, is a Chemical Compound.

2. Carbon is a Chemical Element found as C on the periodic table.

3. Apple Juice is a Heterogeneous Mixture, as it is uniform throughout. If it wasn't uniform, there would be yucky lumps in your apple juice :)

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3 years ago
When the population of organisms in an ecosystem is in balance, we consider the ecosystem to be: A. The ecosystem is in successi
krek1111 [17]
The answer is B. Equilibrium means a state in which opposing forces or influences are balanced.
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3 years ago
A sailor on a trans-Pacific solo voyage notices one day that if he puts 735.mL of fresh water into a plastic cup weighing 25.0g,
Gennadij [26K]

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

According to Archimedes' principle, mass of freshwater and cup = mass of equal volume of seawater

mass of freshwater = density * volume

1 cm³ = 1 mL

mass of freshwater = 0.999 g/cm³ * 735 cm³ = 734.265 g

mass of freshwater + cup = 734.265 + 25 = 759.265 g

Therefore,  mass of equal volume of seawater = 759.265 g

Volume of seawater displaced = 735 mL = 0.735 L (assuming the cup volume is negligible)

1 liter = 1000 cm³ = 1000 mL;

Density of seawater = mass / volume

Density of seawater = 759.265 g / 0.735 L = 1033.01 g/L

Density of freshwater in g/L = 0.999 g/ (1/1000) L = 999 g/L

mass of 1 Liter seawater = 1033.01 g

mass of 1 Liter freshwater = 999 g

mass of salt dissolved in 1 L of seawater = 1033.01 g - 999 g = 34.01 g

Therefore, amount of salt in 1 L seawater = 34 g

4 0
3 years ago
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