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3 years ago

Which transformations in the rock cycle require heat? Select all that apply.

Chemistry

1 answer:

olga55 [171]3 years ago

3 0

Answer:

Igneous rock to metamorphic rock

Metamorphic rock to igneous rock

Sedimentary rock to metamorphic rock

Explanation:

In changing a rock through the listed processes heat is highly required.

Transformation from a rock to igneous rocks requires the most heat because the rock body must be molten.

Igneous rock to metamorphic rock is a metamorphic change that requires significant heat and pressure. The mineralogical fabric is affected by this change.
In moving from metamorphic to igneous rock, the melting temperature of a rock must be attained in order for magma to form.
Sedimentary changes to metamorphic rocks also require heat.

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Which two ions have the same electron configuration?

djverab [1.8K]

Answer: A) Na+ and O2-

Explanation:

To know the electronic configuration, one has to determine the numbers of electrons present in each atom.

Na+ means a sodium atom that has lost one valence electron. A Sodium atom initially has 11 electrons, but having lost an electron making it 10 electrons remaining with electron configuration of 1s2 2s2 2p6.

O2- means oxygen atom that has gained two valence electrons. An oxygen atom initially has 8 electrons, having gained two electrons makes it 10 electrons with electron configuration of 1s2 2s2 2p6. same as Na+

The purpose of gaining or losing electrons is to attain a stable duplet or octet structure.

4 0

3 years ago

Read 2 more answers

Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.

Aleksandr [31]

Answer:

Explanation:

8 0

3 years ago

How many total atoms are in 0.170 g of p2o5?

Pachacha [2.7K]

7.20594 x 10^20

First you must determine how many moles of P3O5 you have. This is done by using the formula
Number of moles (n) = mass in grams of substance (m) /divided by/ Molar mass (M) [this is the sum of the atomic mass of all atoms in the compound]

n = 0.170 / P (31 x 2) + O (16 x 5)
n = 0.170 / 142
n = 0.001197 moles

Then you use avagadros number 6.02 x10^23 this is the number of atoms in one mole of any substance. Since you have 0.001197 moles you multiply the number of moles by avagadros number

0.001197 x (6.02 x 10^23)
= 7.20594 x 10^20 atoms

3 0

4 years ago

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

Regards!

8 0

3 years ago

Draw every stereoisomer for 1,2-difluoro-1,2-dimethylcyclopentane. Use wedge-and-dash bonds for the substituent groups, and be s

Blizzard [7]

Answer:

See figure 1

Explanation:

In this question, we have to find first the chiral carbons on 1,2-difluoro-1,2-dimethylcyclopentane. Carbons 1 and 2. Then, using the Cahn–Ingold–Prelog priority rules. We can draw all the stereoisomers. If we have 2 chiral carbons we will have ( $2^n=2^2=4$ ) 4 isomers. With this in mind we can have the R,R isomer; the S,S isomer; the S,R isomer, and the R,S isomer. We have to remember that:

Priority 1 = "F"

Priority 2= "C"

Priority 3= "CH2"

Priority 4 = "CH3"

I hope it helps!

7 0

4 years ago