2xy + 5x -12y -30
x(2y + 5) - 6( 2y + 5)
(2y+5) (x-6)
2 is the correct answer....gitty up
Answer:
The initial speed of the car was 80 ft/s.
Step-by-step explanation:
The deceleration is the rate at which the car speed decreases. In this case the speed of the car goes all the way down to 0 ft/s and in order to do that it travelled 50 ft. So we will call the initial speed at which the car started to brake "v_0" and use Torricelli's equation to find it. The equation is given by:
v^2 = (v_0)^2 + 2*a*S
Where v is the final speed, v_0 is the initial speed, a is the rate of acceleration and S is the space travelled. Using the values that the problem gave to us we have:
0^2 = (v_0)^2 - 2*64*50
0 = (v_0)^2 - 6400
(v_0)^2 = 6400
v_0 = sqrt(6400) = 80 ft/s
Notice that in this case "a" was negative, since the car was decelerating instead of accelerating.
The initial speed of the car was 80 ft/s.
The formula to calculate the z-score of a certain value is:
z = (x - (mean))/(standard deviation)
In this example, the x-value is 450, the S.D. is 100, and the mean is 500.
So, substitute these values into the formula.
z = (450-(500))/100
z=-50/100
z=-0.5
Therefore, the z-score is -0.5.
that is what the line will look like.
