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pychu [463]
2 years ago
10

How many small cubes with a side length of 2 cm fits in a cube shaped box that has a side length of 10 cm? Show support for your

answer.
Mathematics
1 answer:
MAXImum [283]2 years ago
3 0

Answer:

jk

Step-by-step explanation:

foot jk

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In angle STU, u = 890 cm, t = 810 cm and angle T=38°. Find all possible values of angle U, to the nearest degree.
erastova [34]

Answer:

754435.345345435.43.5435435454.35.34.543534.5.43.5.43.545

Step-by-step explanation:

7 0
3 years ago
Which number line shows the solution to this compound inequality?
serious [3.7K]

Answer:

The explanation is on top x=10

3 0
3 years ago
What is 4 1/3= 1/3 x _/_ = 4 _/_
Oxana [17]
4 1/3 = 13/3 = 1/3 x 13/1 = 4 1/3
3 0
3 years ago
Help me by finding this​
rodikova [14]

n = –1

24/3x=8x^n

8/x=8x^n ]÷8

1/x= x^n

x-¹=x^n

n=–1

7 0
2 years ago
A rectangle has a width of 2.5. When the length of this rectangle is decreased by 5 inches, the new area of the rectangle is 17.
kati45 [8]
<h3><u>Part A: An equation to represent this situation, where x represents the original length of the rectangle is:</u></h3>

17.5 = (x-5) \times 2.5

<h3><u>Part B: Original length of the rectangle is 12 inches</u></h3>

<em><u>Solution:</u></em>

Given that,

A rectangle has a width of 2.5

Therefore,

width = 2.5 inches

Let "x" be the original length of the rectangle

When the length of this rectangle is decreased by 5 inches

Therefore,

New length = x - 5

The new area of the rectangle is 17.5 square inches

Therefore,

<em><u>The area of rectangle is given as:</u></em>

Area = length \times width

17.5 = (x-5) \times 2.5\\\\17.5 = 2.5x - 12.5\\\\2.5x = 17.5 + 12.5\\\\2.5x = 30\\\\x = 12

Thus original length of the rectangle is 12 inches

7 0
3 years ago
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