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2 years ago

10

How many small cubes with a side length of 2 cm fits in a cube shaped box that has a side length of 10 cm? Show support for your

answer.

1 answer:

MAXImum [283]2 years ago

3 0

Answer:

jk

Step-by-step explanation:

foot jk

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Venetta buys 2 pounds of pistachios and 3 pounds of almonds. The pistachios cost $4 more per pound than the almonds. She pays a

Alex

Answer: the answer is 2 and 5

Step-by-step explanation:

8 0

3 years ago

A projectile was launched straight up from the ground with an initial velocity of 48 ft/s. The height of the projectile t second

alex41 [277]

Factor f(t) and you can identify the values of t for which the height is zero.
.. f(t) = -16t(t -3)

The projectile lands after 3 seconds in the air. (selection A)

8 0

3 years ago

Katha walks 5 blocks east. Then she walks straight back to where she started and walks 5 blocks west.

anyanavicka [17]

Answer:

5 is the point on the number line how far she walked east

0 is the point on the number line where she began walking

-5 is the point on the number line how far she walked west

Step-by-step explanation:

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3 years ago

A number cube with faces labeled from 1 to 6 will be rolled once.

kramer

Answer:

$\Omega=\{1,2,3,4,5,6\}$

$A=\{1,2,3,4\}$

Step-by-step explanation:

<u>Sample Space</u>

The sample space of a random experience is a set of all the possible outcomes of that experience. It's usually denoted by the letter $\Omega$ .

We have a number cube with all faces labeled from 1 to 6. That cube is to be rolled once. The visible number shown in the cube is recorded as the outcome. The possible outcomes are listed as the sample space below:

$\Omega=\{1,2,3,4,5,6\}$

Now we are required to give the outcomes for the event of rolling a number less than 5. Let's call A to such event. The set of possible outcomes for A has all the numbers from 1 to 4 as follows

$A=\{1,2,3,4\}$

3 0

3 years ago

The graph of g(x)=(0.5)x+4 is shown. Which equation is an asymptote of this function? y = 0 y = 4 x = 4 x = 0

Alexandra [31]

we are given

$g(x)=(0.5)^x+4$

we can see that

there is no value of x for which g(x) is not defined

so, no vertical asymptote exists

now, we will find horizontal asymptote

$\lim_{x \to \infty} g(x)= \lim_{x \to \infty}((0.5)^x+4 )$

$\lim_{x \to \infty} g(x)= (\lim_{x \to \infty} (0.5)^x+\lim_{x \to \infty} 4 )$

$\lim_{x \to \infty} g(x)= 0+4$

so, we get

horizontal asymptote as

$y= 4$ ............Answer

3 0

2 years ago