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Inga [223]
3 years ago
14

The diagram below shows several parking spots near the grocery store, formed with three parallel line segments and a transversal

. If the measure of angle 4 is 132°, what is the measure of angle 7? 32° 48° 132° 148°

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0
Something I noticed about angle 4, is that it shares a straight line with angle 3. (above it is a straight line)

A straight line equals 180 degrees.

So, angle 4 + angle 3= 180 degrees.

Angle 3 is congruent to angle 7.

180-132= Angle 7

180-132= 48

48 degrees is your answer.

I hope this helps!
~kaikers

NNADVOKAT [17]3 years ago
4 0

The answer is 48 degrees. I tool the test and it said that this was correct.

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Answer:

12

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9

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Step-by-step explanation:

<h3>i.a+7 for a=5</h3>

5+7=12

<h3>ii.8(c+3) for c =9</h3>

8(9+3)

8(12)

96

<h3>iii.n+8 divided by 4 for n=28</h3>

=28+8 divided by 4

=36 divided by 4

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<h3>iv.6p+40 divided by 5 for p =5</h3>

=6×5+40 divided by 5

=30+40 divided by 5

=70 divided by 5

=38

<h3>v.3x+7 for x=6</h3>

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3 years ago
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Step-by-step explanation:

A fraction is in simplest form when the top and bottom cannot be any smaller, while still being whole numbers. To simplify a fraction: divide the top and bottom by the greatest number that will divide both numbers exactly (they must stay whole numbers).

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I have 90% after about 75%
kkurt [141]

The lowest grade he could earn is 120% of the grade at the end of the semester.

The following statement is given:

I have 90% after about 75% of the semester.

We are asked to find the lowest grade by the end of this semester.

<h3>What is Percentage?</h3>

A percentage is a number expressed as a fraction of 100.

- 50% = 50/100 = 1/2

- 25% = 25/100 = 1/4

- 20% = 20/100 = 1/5.

We can write this statement "I have a 90% grade after about 75% of the semester" as:

90% grade  =  75% semester.............(1)


By the end of the semester means at 100% semester.

Multiplying equation (1) by 100/ 75 on both sides of the equation.

We get,

(100/75) x 90% grade = (100/75) x 75% semester

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Thus the lowest grade he could earn is 120% of the grade at the end of the semester.

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