Answer:
The mass percentage of the solution is 10.46%.
The molality of the solution is 2.5403 mol/kg.
Explanation:
A bottle of wine contains 12.9% ethanol by volume.
This means that in 100 mL of solution 12.9 L of alcohol is present.
Volume of alcohol = v = 12.9 L
Mass of the ethanol = m
Density of the ethanol ,d= 


Mass of water = M
Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL
Density of water = D=1.00 g/mL

Mass percent


Molality :

M = 87.1 g = 0.0871 kg (1 kg =1000 g)


Answer:
You need the Delta H fusion for water. Multiply that by 50 grams. Then multiply 50 g x 4.184 x 65 to get joules to raise water to 65 degrees. Add these values together to get total joules.
Explanation:
Answer:Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because the bromine radical is less reactive and therefore more selective.
Explanation: Halogenation occurs when a halogen replaces one or more hydrogen atoms in an organic compound ie chlorine or bromine with the reactivity of the halogens decreasing in the order of F2 > Cl2 > Br2 > I2
Since fluorine reacts explosively making it is difficult to control, and iodine is unreactive. Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine with Chlorination ie chlorine radical being more reactive and not selective and the Bromination of alkanes ie bromine radical occurring similarly but slower and less reactive but more selective which is due to the fact that a bromine atom is less reactive in the hydrogen abstraction than a chlorine atom evidence in the higher bond energy of H-Cl than H-Br.
Answer:
A base is weak when only a little of it is dissolved in water
Explanation:
Answer:
0.067 M
Explanation:
Given data:
Volume of solution = 1.00 L
Mass of BaCl₂ = 14 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will calculate the number of moles first.
Number of moles = mass/ molar mass
Number of moles = 14 g/ 208.23 g/mol
Number of moles = 0.067 mol
Now we will calculate the molarity.
Molarity = 0.067 mol / 1.00 L
Molarity = 0.067 M ( mol/L=M)