Answer:
94.1 %
Explanation:
We firstly determine the equation:
2H₂O + O₂ → 2H₂O₂
2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.
We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol
Certainly oxygen is the limiting reactant.
2 moles of water react to 1 mol of oxygen.
13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)
As we determine the limiting reactant we continue to the products:
1 mol of O₂ can produce 2 moles of H₂O₂
Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles
We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g
That's the 100% yield or it can be called theoretical yield.
Percent yield = (Yield produced / Theoretical yield) . 100
(100g / 106.25 g) . 100 = 94.1 %
Answer:
The atomic weight of hypothetical element will be 63.568 amu.
Explanation:
Given data:
First isotope mass = 62.2 amu
Percentage abundance of first isotope = 24%
Mass of second isotope = 64 amu
Percentage abundance of second isotope = 100- 24 = 76%
Solution:
The atomic weight of hypothetical element will be the average atomic mass of its isotopes.
Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100
Now we will put the values in formula.
Average atomic mass = [24 ×62.2] + [76× 64] / 100
Average atomic mass = 1492.8 + 4864 / 100
Average atomic mass = 6356.8/100
Average atomic mass = 63.568 amu
Answer:
thhe anwer is d
Explanation:
the answer is d just took the quiz got 100 on edge 2022
