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2 years ago

When a solution becomes more acidic, does its pH increase or decrease? Explain up to 2 to 4 sentences.

Chemistry

2 answers:

Amanda [17]2 years ago

4 0

Answer:

it's ph decreases.. meaning those with a small ph value are more acidic.forinstance one with a ph of 1 is more acidic than the one with a ph of 3.

I hope this helps

Colt1911 [192]2 years ago

3 0

Answer:

it decrease when a solution becomes more acidic which means that decrease in pH means increase..

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A student dropped a piece of nickel metal into a solution of HCl(aq). He observed the formation of gas bubbles and collected the

omeli [17]

Answer:

a. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.

Explanation:

It is given that a student performed an experiment where he dropped a nickel metal in to HCl solution. He observed the reaction and performed a splint test in the test tube that is filled with a gas which is formed while Nickle is dropped into the solution of HCl.

But the experiment that the student performed was incorrect. He must have observed the popping sound when the splint was placed in the test tube.

When the splint was added to the gas splint flared up. The hydrogen gas pops out when exposed to the flame.

$Ni + HCl(aq) = NiCl + H_2$

Thus the correct option is (a).

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3 years ago

People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m

Llana [10]

Answer:

$V_{HCl}=0.208L=208mL$

Explanation:

Hello,

In this case, since the chemical reaction is:

$2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O$

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

$n_{HCl}=2*n_{Mg(OH)_2}$

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

$n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g} =0.00858mol$

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

$[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M$

Then, since the concentration and the volume define the moles, we can write:

$[HCl]*V_{HCl}=2*n_{Mg(OH)_2}$

Therefore, the neutralized volume turns out:

$V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL$

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3 years ago

A particular graduated cylinder contains 24.0 mL Br2(liquid). The density of bromine at 25 degrees C is 3.12g/cm^3. Note that in

motikmotik

Answer:

$2.82x10^{23}molecules$

Explanation:

Hello.

In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:

$\rho =\frac{m}{V}$

$m=\rho *V=3.12g/cm^3*24.0cm^3\\\\m=74.88gBr_2$

Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:

$n=74.88g*\frac{1mol}{159.82g} =0.469molBr_2$

Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:

$particles=0.469mol*\frac{6.022x10^{23}molecules}{1mol}\\ \\2.82x10^{23}molecules$

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3 years ago

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The answer is B because i just took the test

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Ipatiy [6.2K]

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