Answer:
l = 0 → s = 2 electrons;
l = 1 → p = 6 electrons;
l = 2 → d = 10 electrons;
l= 3 → f = 14 electrons.
Explanation:
For the quantum theory, the probability to find an electron is higher in the space region called orbital. It's impossible to determine where the electron is and his velocity at the same time (uncertainty principle). So, the theory determines four quantum numbers to characterize an electron, so it's easy to identify it:
- n is the principal quantum number and identify the shell where the electron is. It varies from 1 to 7 and is represented by the letters K, L, M, N, O, P, and Q;
- l is the azimuthal quantum number and identify the subshell (or sublevel) where the electron is. It varies from 0 to 3 and is represented by the letters s, p, d, and f;
- ml is the magnetic quantum number, and it represents the orbital. It varies from -l to +l, passing by 0. Each orbital can have at least 2 electrons;
- ms is the spin number and represents the spin of the electrons. It can be +1/2 or - 1/2.
Then, the sublevel s (l= 0) only has 1 orbital (ml = 0) so, it can have ate least 2 electrons; the sublevel p (l= 1) has 3 orbitals (ml = -1, ml= 0, ml = +1), so it can have at least 6 electrons; the sublevel d (l = 2) has 5 orbitals (ml = -2, ml = -1, ml = 0, ml = +1, ml = +2), so it can have at least 10 electrons; and the sublevel f (l = 3) has 7 orbitals (ml = -3, ml = -2, ml = -1, ml = 0, ml = +1, ml = +2, ml = +3), so it can have at least 14 electrons.
It is 292.5 m because you do 4.5 hours times 65. (please give me brainliest)
The average atomic mass of the hypothetical element is the sum of the products of the isotopes and their percentage abundance. For this given,
atm = (84.95 amu)(0.371) + (86.95 amu)(0.629)
= 86.208 amu
Thus, the average atomic mass of the element is 86.208 amu.
The answer is d.HCl hope this helps
