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scoray [572]
3 years ago
5

A pharmaceutical company claimed that experiments showed that its drug could effectively reduce the growth of cancer cells by 35

percent. However, when five independent laboratories conducted the same experiment, they measured a reduction rate of only 5–8 percent. How did these laboratories show that the pharmaceutical company’s claims were invalid?
Chemistry
2 answers:
algol [13]3 years ago
6 0

Answer:

D. The labs were unable to reproduce the pharmaceutical company’s data

Explanation:

I took the test.

BaLLatris [955]3 years ago
4 0

Answer :  The labs were unable to reproduce the pharmaceutical company’s data.

Explanation : Any scientific claim must have reproducible experimental data. In this case, when the pharmaceutical company has the claim of reducing the cancer growth cells by 35% then by using the same manufacturing procedure for the drug and lab should be able to get this result. But they failed to match up with the results which clearly indicates that the labs were not able to produce the same results and hence they concluded that the pharmaceutical company's claims were invalid.

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The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hert
Fed [463]

Answer:

6.56×10¹⁴ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength = 457 nm

Frequency =?

Next, we shall convert 457 nm to metre (m). This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

457 nm = 457 nm × 1×10¯⁹ m / 1 nm

457 nm = 4.57×10¯⁷ m

Thus, 457 nm is equivalent to 4.57×10¯⁷ m

Finally, we shall determine the frequency of the blue light as follow:

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Velocity of light = 3×10⁸ m/s

Frequency =?

Velocity = wavelength x frequency

3×10⁸ = 4.57×10¯⁷ × frequency

Divide both side by 4.57×10¯⁷

frequency = 3×10⁸ / 4.57×10¯⁷

frequency = 6.56×10¹⁴ Hz

Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz

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