Answer:
Chemical reactions do not involve changes in the chemical bonds that join
atoms in compounds :
<u>False</u>
Explanation:
Chemical reaction are the reaction in which old bonds break and new bonds are formed . The formation of new bond result in formation of new compounds . This happen because new bond are result of linking different atoms by the bond.
For example : Water formation from Oxygen and Hydrogen is a chemical process :
Original(old) bonds are :
H-H bond in H2 and O-O bonds in O2
In H2 = Hydrogen is joined to Hydrogen
IN O2 = Oxygen is joined to oxygen
New Bonds =
O-H bonds in water (H2O)
Oxygen is joined to hydrogen = New Bond formation
Hence,
<u>Chemical reactions do involve changes in the chemical bonds that join
</u>
<u>atoms in compounds</u>
<u />
Mole ratio :
<span>5 C</span>₆<span>H</span>₆<span>CHO + 2 KMnO</span>₄<span> + 6 H</span>⁺ <span>= 5 C</span>₆<span>H</span>₆<span>COOH + 2 Mn</span>²⁺<span> + 3 H</span>₂<span>O + 2 K</span>⁺
5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )
moles of KMnO₄ = 1.0 x 2 / 5
moles of KMnO₄ = 2 / 5
= 0.40 moles of KMnO4
hope this helps!
Answer:
239.15. OR round down 239
Explanation:
First, we convert the masses into fractions
<span>138 g of benzene = 1.77 moles benzene
91.2 g of heptane = 0.93 moles heptane
Next, calculate the mole fractions
x1 (benzene) = 1.77 / (1.77 + 0.93) = 0.66
x2 (heptane) = 1 - 0.66 = 0.34
</span>The vapor pressure of pure benzene is 322 torr at 40 C.
At the same temperature, the vapor pressure of heptane is 92 torr.
<span>
The partial pressure of benzene is
p1 = 0.66 (322) = 212.52 torr
The partial pressure of heptane is
p2 = 0.34 (92) = 31.28 torr
</span>
After studying the graph,the evidence from the bright line spectra that indicates element A is not present in the mixture is 11 the lines of A are not present in the mixture 700 nm is missing.
