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scoray [572]
3 years ago
5

A pharmaceutical company claimed that experiments showed that its drug could effectively reduce the growth of cancer cells by 35

percent. However, when five independent laboratories conducted the same experiment, they measured a reduction rate of only 5–8 percent. How did these laboratories show that the pharmaceutical company’s claims were invalid?
Chemistry
2 answers:
algol [13]3 years ago
6 0

Answer:

D. The labs were unable to reproduce the pharmaceutical company’s data

Explanation:

I took the test.

BaLLatris [955]3 years ago
4 0

Answer :  The labs were unable to reproduce the pharmaceutical company’s data.

Explanation : Any scientific claim must have reproducible experimental data. In this case, when the pharmaceutical company has the claim of reducing the cancer growth cells by 35% then by using the same manufacturing procedure for the drug and lab should be able to get this result. But they failed to match up with the results which clearly indicates that the labs were not able to produce the same results and hence they concluded that the pharmaceutical company's claims were invalid.

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A. Choose one of the four biogeochemical cycles that were discussed in this unit - carbon, nitrogen, water, or oxygen and descri
MAVERICK [17]

Water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

<h3>What is are the stages of water cycle?</h3>

These are the basic stages through which water passes. These stages are:

  • Evaporation
  • Condensation
  • Precipitation
  • Collection.

So therefore, water cycle simply refers to the continuous movement or flow of water from the atmosphere to the earth and back to the atmosphere

Learn more about water cycle:

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#SPJ1

6 0
2 years ago
Part A Name the complex ion [Fe(CN)6]^3- . The oxidation number of iron is +3. Part B Name the complex ion [Cu(NH3)2(H2O)4]^2+ .
zvonat [6]

Answer:

Part A: Hexacyanoferrate (III)

Part B: DiammintetraaquoCupperate (II)

Part C: Dichlorobis(ethylenediamine) Chromate (II)

Part D: Triaquocarbonylnickel (II) Sulphate

Part E: Potassium Dicarbonatedifluoroplatinate (II)

Explanation:

For naming the complex ions there is a specific rule

Nomenclature of the complex ions are as follow

  • write a correct formulae
  • Indicate the oxidation number of metal in the complex
  • The oxidation number should write in the roman numeral in perenthasis after metal name
  • Ligand named before the metal ion
  • Ligan can be named in following order

                  * 1st negative,  2nd neutral, 3rd positive

                  * If there are more than 2 same charged ligand the write in                      

                    alphabetical order.

  • Write prefix i.e di, tri, tetra for multiple monodentate ligands
  • Anions name end at ido the replace the final name.
  • Neutral ligands named as their usual name, but there are some exceptions such as

                                      NH3 named as ammine

                                      H2O names aqua or aquo

                                     CO named ascarbonyl

                                      NO named as nitrosyl

  • If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
  • The name of full complex will end with cation or anion with separate word.  

Keeping the rules in mind the complexes named as following.

_________________________

Part A:

[Fe(CN)₆]³⁻

Name of the Complex : Hexacyanoferrate (III)  

___________________

Part B:

[Cu(NH₃)₂(H₂O)₄]²⁺

Name of the Complex : DiammintetraaquoCupperate (II)

_______________________

Part C

CrCl₂(en)₂

Name of the Complex :  Dichlorobis(ethylenediamine) Chromate (II)

________________________

Part C

[Ni(H₂O)₃(CO)]SO₄

Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate

______________________

Part E

K₄[Pt(CO₃)₂F₂]

Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)

5 0
3 years ago
One mole of hydrogen atoms contains 6.022 x 1023 atoms (Avogadro’s number) and occupies a volume of 22.4 L. How many hydrogen at
AleksAgata [21]

Answer:

The answer to your question is 6.72 x 10²⁰ atoms

Explanation:

Data

Avogadro's number = 6.022 x 10²³ atoms

Volume = 22.4 L

Volume 2 = 25 ml

Number of atoms = ?

Process

1.- Convert mL to L

                              1000 mL  ----------------- 1 L

                                  25 mL ------------------  x

                                  x = (25 x 1) / 1000

                                  x = 25 / 1000

                                 x = 0.025 L

2.- Use proportions and cross multiplication to find the answer.

                                 22.4 L ----------------- 6.023 x 10²³ atoms

                                 0.025 L --------------   x

                                 x = (0.025 x 6.023 x 10²³) / 22.4

                                 x = 1.51 x 10²² / 22.4

                                 x = 6.72 x 10²⁰ atoms

6 0
3 years ago
Which of the following metamorphic rocks would most likely have formed at the highest temperatures and pressures?
galina1969 [7]

gneiss is your answer

7 0
4 years ago
Read 2 more answers
If 2.65 mol of O2 gas has a volume of 49.0 L at 180 C, what is the pressure of the gas?
adoni [48]

Answer:

2.01atm

Explanation:

5 0
3 years ago
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