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3 years ago

How much heat is required to warm 1.30 l of water from 24.0 ∘c to 100.0∘c? (assume a density of 1.0g/ml for the water.)?

1 answer:

5 0

When q = M* C *ΔT

we can get the mass using the given volume & density:

M = volume * density

= 1.3 L * 1g/ml * 1000mL1L

= 1300 g
and when the specific heat of water = 4.18J/g.°C

now, by substitution:

∴ q = 1300g * 4.18J/g.°C * (100-24)

= 412984 J or 412.984 KJ

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The number of mitochondria in an animal cell varies. Mitochondria are found more in active cells like liver and less in hair cel

laiz [17]

Answer:

Make high energy molecules for the cell to function.

Explanation:

Remember mitochondria is the storehouse of the cell.

Hope it helps!

6 0

3 years ago

Copper reacts with silver nitrate through single replacement.

-Dominant- [34]

Answer:

Part a) 0.0104 moles copper(II) nitrate.

Part b)

i) 0.0418 mole Cu

ii) 0.0209 mol Ag NO₃

Explanation:

1) Balanced chemical reaction (single replacement):

In a single replacement reaction a more acitve metal (Cu) replaces a less active metal (Ag)

Cu + 2 Ag NO₃ → Cu (NO₃)₂ + 2 Ag

2) Mole ratio:

1 mole Cu : 2 mole Ag NO₃ : 2 mole Ag

3) Moles of Ag

n = mass in grams / atomic mass
atomic mass of Ag: 107.868 g/mol
n = 2.25 g / 107.868 g/mol = 0.0209 mol Ag

4) Moles of copper(II) nitrate:

Set the proportion using the mole ratio:

2 mole Ag / 1 mole Cu (NO₃)₂ = 0.0209 mole Ag / x

Solve: x = 0.0209 / 2 mole Cu (NO₃)₂ = 0.0104 moles Cu(NO₃)₂

That is the answer of part a: 0.0104 moles copper(II) nitrate.

5) Moles of each reactant

i) Cu:

Set a proportion using the theoretical mole ratio

1 mole Cu / 2 mole Ag = x / 0.0209 mol Ag

Solve for x: x = 0.0209 / 2 mole Cu = 0.0418 mole Cu

ii) Ag NO₃

Set a proportion using the teoretical mole ratio

2 mole Ag NO₃ / 2 mole Ag = x / 0.0209 mole Ag

Solve for x: x = 0.0209 mol Ag NO₃

6 0

4 years ago

You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio

irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

Substituting the respective values ,

M₁ * 125.0 mL = 4.56 M * 134.1 mL

M₁ = 4.90 M

6 0

4 years ago

List 10 chemical reactions reactions that have benefited your life today. include the reason you think each was indeed a chemica

vagabundo [1.1K]

Answer:

your answer may be found on a website called "Thought.co"

once you get there just search "Examples of Chemical Reactions in Everyday Life" and it will give you some ideas :)

7 0

3 years ago

What is the daughter nucleus (nuclide) produced when 227th undergoes alpha decay?

Elina [12.6K]

Answer: -

²²³Ra is the daughter nuclide produced when ²²⁷Th undergoes alpha decay

Explanation: -

When alpha decay occurs, the mass number of the parent decreases by 4 and the atomic number decreases by 2.

Mass number of ²²⁷Th =227

Atomic number of ²²⁷Th = 90

Mass number of daughter = 227 - 4 = 223

Atomic number of daughter = 90 - 2 = 88

88 is the atomic number of Ra Radium.

Thus the daughter is ²²³Ra

6 0

3 years ago