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2 years ago

What is the slope-intercept form 10x-7y=-8

Mathematics

1 answer:

Dafna1 [17]2 years ago

4 0

Answer:

Step-by-step explanation:

Slope intercept form: y = mx +b

10x - 7y = -8

-7y = - 10x - 8

Divide the equation by (-7)

$\dfrac{-7y}{-7}=\dfrac{-10x}{-7} +\dfrac{-8}{-7}\\\\\\y =\dfrac{10}{7}x+\dfrac{8}{7}$

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1 point

Elan Coil [88]

Your current balance if you started the day with $100 in your account is $73

First step is to calculate the total cash at bank

Using this formula

Total Cash at bank= Cash at bank + Deposit

Let plug in the formula

Total Cash at bank=$100+90

Total Cash at bank=$190

Second step is to calculate the amount debited

Debit amount=($60+$3)+($34+$20)

Debit amount=$63+$54

Debit amount=$117

Now let determine your current balance

Current balance=Total cash at bank-Amount debited

Let plug in the formula

Current balance=$190-117

Current balance=$73

Your current balance if you started the day with $100 in your account is $73

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2 years ago

What is the answer of Three over Four multiply to eight over nine ?

andrew11 [14]

The answer would be 2 over 3, or 2/3. (:

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3 years ago

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avanturin [10]

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The area is 252

Step-by-step explanation:

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2 years ago

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Tcecarenko [31]

Step-by-step explanation:

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3 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

3 years ago