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2 years ago

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

Mathematics

1 answer:

Kaylis [27]2 years ago

3 0

Answer:

Adults $ 17

Students: $8

Step-by-step explanation:

Adults: x

Students: y

a) 25x + 31y = 673

b) 27x +31y = 707

Elimination:

a) -1(25x + 31y = 673) = -25 -31y = -673

a + b

= (-25 -31y = -673) + (27x + 31y = 707)

= 2x = 34

x = 34/2

x = 17

Substitution a or b:

a) 25(17) + 31y = 673

425 + 31y = 673

31y = 673 - 425

31y = 248

y = 248/31

y = 8

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Link is coloring a triforce, which consists of four equilateral triangles and is depicted below. He has three colors to use: gol

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Answer:

Step-by-step explanation:

For the top triangle, he has 3 options

3C1 = 3

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2C1 = 2

For the ones on sides of the middle one, 2 options each

2C1 × 2C1 = 4

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Also, these include 2 of the three outer ones same, so subtract:

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3 years ago

Read 2 more answers

If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.

Ierofanga [76]

According to the identity if a+b+c=0
then a3+b3+c3=3abc
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cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved

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3 years ago

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ICE Princess25 [194]

Answer:

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Step-by-step explanation:

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2 years ago

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The answer is a 12% increase.

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3 years ago

20 points! Will mark the brainliest!

andrew-mc [135]

$\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }$

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Write the divide fraction horizontally:
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$= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}$

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Factorise the numerators and denominators when possible:
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$= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}$

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Convert the divide fraction to multiplication fraction
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$= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}$

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Cancel the factors
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$= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}$

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Combine to single fraction
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$= \dfrac{1}{4(x+2)^2}$

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3 years ago