Answer:
Relative molecular of the compound or infomation like vapour density, volume occupied by a known mass of its vapour at stp, etc
Explanation:
The molecular mass of a compound is twice its vapour density. We can find the molecular formula using the relationship below:
- Empirical formula is the simplest formula of a compound. It repeats itself "n" times to become a molecular formula i.e (EF)ₙ = MF...... n is the number of times the empirical formula presents in a mole of the compound.
- Most times, n is a whole number like 1,2,3,.....
It would be group 1, the alkali metals and group 17, the halogens.
Hope this helps! (:
Answer:
Solution
dT = K * b
K (H2O) = 1.86 0C
b(C2H6O2) = dT/ K = 33.2 / 1.86 = 17.85(mol/kg)
b(C2H6O2)= n (C2H6O2) / m (H2O)
m (H2O) = V * = 12.2 * 1 = 12.2 (kg)
n (C2H6O2) = b (C2H6O2) * m (H2O) = 17.85 * 12.2 = 217.77 (mol)
n (C2H6O2) = m / M;
m (C2H6O2) = n * M = 217.77 * (12*2 + 1*6 + 16 *2) = 13501.74 (g) = 13.5 (kg)
V (C2H6O2) = m / = 13.5 / 1.11 = 12.16 (L)
Answer V (C2H6O2) = 12.16 L
Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!
Answer:
50 Points Help 1) Find the mass of 250.0 mL of benzene. The density of benzene is 0.8765 g/mL.
7) What volume of silver metal will weigh exactly 2500.0 g. The density of silver is 10.5 g/cm3.
Answer:
At 13.6 C, a 1.2 mole sample of a gas exerts a pressure of 2.4 atmospheres. 1 point If you were solving for volume, what number would you use for temperature in the ideal gas law equation (PV = nRT)? о O 13.6 o 1.2 0 24 O 286.6 0 275.4
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