Question

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

Answer 1

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ $(P+\frac{n^2 a}{v^2} )(v-nb)=nRT$

or,

⇒ $P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}$

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ $P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}$

       $=\frac{(0.467)^2\times 3.49}{(0.245)^2}$

       $=73.61-13.05$

       $=60.56 \ atm$