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3 years ago

Determine the balanced chemical equation for this reaction. C8H18(g)+O2(g)→CO2(g)+H2O(g)

Chemistry

1 answer:

ankoles [38]3 years ago

4 0

Answer: balanced reaction equation

C8H18(g) + 25/2 O2(g) ---------> 8CO2(g) + 9H2O(l)

Explanation:

Part A- coefficients

1, 25/2,8,9

Part B

Oxygen is the limiting reactant

Part C

If 1 mole of octane produced 9 moles of water from the balanced reaction equation

0.28 moles of octane will produce 0.28×9= 2.52 moles of water

Part D

If 12.5 moles of oxygen reacts with 1 mole of octane

0.63 moles of oxygen will react with 0.63/12.5=0.0504moles of octane

Amount of octane left= 0.280-0.0504=0.2296 moles

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3 years ago

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Which statement below is not a premise of the Kinetic-molecular theory of gases?

zhuklara [117]

Answer:

d = all are premise of KMT.

Explanation:

Gas particles are extremely small and have relatively large distance between them.

Gas particles are continuously moving in random, straight-line motion as they are collide with each other and the container walls.

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2 years ago

Type the correct answer in each box.

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Answer:

mg3n2 and cacl3 hope it helps

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3 years ago

Acid formulas usually start with ______________ because they have hydrogen atoms combined with other atoms in their molecules

mina [271]

Answer:

Explanation:

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3 years ago

Determine the number of moles in 258.45 grams of iron (III) chloride (FeCl3). Show and explain all

QveST [7]

Answer:

$\boxed {\boxed {\sf 1.5935 \ mol \ FeCl_}}$

Explanation:

To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. First, find the molar mass of iron and chlorine.

Fe: 55.84 g/mol
Cl: 35.45 g/mol

Check the formula. There is a subscript of 3 after Cl, so there are 3 atoms of chlorine in 1 molecule. Multiply iron's molar mass by 3, then add iron's molar mass.

FeCl₃: 55.84 + 3(35.45) = 55.84+106.35=162.19 g/mol

Use this number as a ratio.

$\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}$

Multiply by the given number of grams.

$258.45 \ g \ FeCl_3 *\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}$

Flip the ratio so the grams of iron (III) chloride cancel.

$258.45 \ g \ FeCl_3 *\frac {1 \ mol \ FeCl_3}{162.19 \ g\ FeCl_3}$

$258.45 *\frac {1 \ mol \ FeCl_3}{162.19}$

$\frac {258.45 \ mol \ FeCl_3}{162.19}$

$1.59350144892 \ mol \ FeCl_3$

The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

$1.5935 \ mol \ FeCl_3$

258.45 grams is approximately 1.5935 moles of iron (III) chloride.

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3 years ago