Answer : The volume of gas required to provide 18.01L of gas at the surface is, 3.6 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 12.8 atm
= final pressure of gas = 1.0 atm
= initial volume of gas = ?
= final volume of gas = 18.01 L
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
Therefore, the volume of gas required to provide 18.01L of gas at the surface is, 3.6 L
Answer:
The 3rd answer down.
Na²O (sodium oxide) will be a base when exposed to water H²O
Explanation:
Sodium Oxide Na²O, will become Sodium Hydroxide after being exposed to water (at 80% I believe).
The oxygen ion in Na²O has 2 extra electrons which makes it highly charged and very attractive to hydrogen ions. The attraction is so strong that when Na²O comes in contact with H²O, the O(-2) strips off a hydrogen from water, forming 2 x OH ions which of course are still strongly basic.
In this question, you are given the NaOH volume but asked for concentration.
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:
OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
8.25 grams of O2 has 0.258 moles of Oxygen. Here's how you figure that out:
Oxygen is one of the 7 diatomic elements, so it is normally O2.
<span>You find it's molar mass (or mass for </span>one mole<span> of it) by adding up two of the masses from the Periodic Table.</span>
