Answer: balanced reaction equation
C8H18(g) + 25/2 O2(g) ---------> 8CO2(g) + 9H2O(l)
Explanation:
Part A- coefficients
1, 25/2,8,9
Part B
Oxygen is the limiting reactant
Part C
If 1 mole of octane produced 9 moles of water from the balanced reaction equation
0.28 moles of octane will produce 0.28×9= 2.52 moles of water
Part D
If 12.5 moles of oxygen reacts with 1 mole of octane
0.63 moles of oxygen will react with 0.63/12.5=0.0504moles of octane
Amount of octane left= 0.280-0.0504=0.2296 moles