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hammer [34]
3 years ago
5

Compare 7 x 103 and 5 x 102. A) 7 x 103 is 14 times larger than 5 x 102. B) 7 x 103 is 4 times larger than 5 x 102. C) 7 x 103 i

s twice as large as 5 x 102. D) 7 x 103 is 5 times larger than 5 x 102.
Mathematics
1 answer:
Tom [10]3 years ago
8 0
7 * 10^3 = 7 * 1000 = 7000
5 * 10^2 = 5 * 100 = 500

7000/500 = 14

so 7 * 10^3 is 14 times larger then 5 * 10^2 <==
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John left school with 8.43 he found a quarter on his way home and then stopped to buy an Apple for 0.89 . how much money did he
larisa [96]

Answer:

7.79

Step-by-step explanation:

8 0
3 years ago
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A car travels 258 miles in 312 minutes at a constant speed. Which equation represents the distance, d, that the car travels in m
pashok25 [27]

Answer:

0.83 miles per minute

Step-by-step explanation:

The speed of the car can be found by dividing the distance by the time. THe distance is 258 miles and the time is 312 minutes.

s=\frac{d}{t} \\s=\frac{258}{312} \\s=0.83

6 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

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4 0
3 years ago
What is the solution set for the inequality,
creativ13 [48]

Answer:

x≤−6

Step-by-step explanation:

Let's solve your inequality step-by-step.

4(x−3)−7x≥6

Step 1: Simplify both sides of the inequality.

−3x−12≥6

Step 2: Add 12 to both sides.

−3x−12+12≥6+12

−3x≥18

Step 3: Divide both sides by -3.

−3x

−3

≥

18

−3

x≤−6

6 0
3 years ago
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The population of a town is 13,000. It decreases at a rate of 5% per year. In about how many years will the population be less t
just olya [345]

This is an exponential decay problem.

Using the equation Y = a *(1-rate)^time

where Y is the future value given as 12,000 and a is the starting value given as 13,000.

The rate is also given as 5%.

The equation becomes:

12,000 = 13,000(1-0.05)^x

12,000 = 13,000(0.95)^x

Divide each side by 13000:

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Use the natural log function:

x = ln(12/13) / ln(0.95)

x = 1.56 years. ( this will equal 12,000

Round to 2 years it will be less than 12000.

3 0
4 years ago
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