A

How many diagonals can be drawn in the shape below? 7 8 9 10

vladimir2022 [97]

There are 9 diagonals.

Please see the attached picture for all the vertices that are drawn. When you start drawing the diagonals, be cautious of the ones that you have already drawn.

4 0

3 years ago

Someone help please want asap

Margaret [11]

Answer:

3

Step-by-step explanation:

you are dividing by 3 each time

3 0

3 years ago

The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions

ruslelena [56]

Answer:

Expression B: 0.8p

Expression D: p - 0.2p

Step-by-step explanation:

The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions shown below represent the sale price, in dollars, of the item.

Expression A: 0.2p

Expression B: 0.8p

Expression C:1 - 0.2p

Expression D: p - 0.2p

Expression E: p - 0.8p

Which two expressions each represent the sale price of the item?

Regular price of the item = $p

Sale price = 20% off regular price

Sale price = $p - 20% of p

= p - 20/100 * p

= p - 0.2 * p

= p - 0.2p

= p(1 - 0.2)

= p(0.8)

= 0.8p

The sale price is represented by the following expressions

Expression B: 0.8p

Expression D: p - 0.2p

3 0

3 years ago

What is the factor of 4x^2-16y^2

sweet-ann [11.9K]

4(x+2y) (x-2y)
hope this helps

5 0

3 years ago

General Hospital has noted that they admit an average of 9 patients per hour.

serious [3.7K]

Answer:

(a) The probability that during the next hour less than 3 patients will be admitted is 0.00623.

(b) The probability that during the next two hours exactly 8 patients will be admitted is 0.00416.

Step-by-step explanation:

The complete question is: General Hospital has noted that they admit an average of 8 patients per hour.

(a) What is the probability that during the next hour less than 3 patients will be admitted?

(b) What is the probability that during the next two hours exactly 8 patients will be admitted?

The above situation can be represented through Poisson distribution as it includes the arrival rate of the pattern. So, the probability distribution of the Poisson distribution is given by;

$P(X = x) = \frac{e^{-\lambda} \times \lambda^{x} }{x!} ; x = 0,1,2,......$

Here X = Number of patients admitted in the hospital

$\lambda$ = arrival rate of patients per hour = 9 patients

So, X ~ Poisson( $\lambda$ = 9)

(a) The probability that during the next hour less than 3 patients will be admitted is given by = P(X < 3)

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

= $\frac{e^{-9} \times 9^{0} }{0!} + \frac{e^{-9} \times 9^{1} }{1!} + \frac{e^{-9} \times 9^{2} }{2!}$

= $e^{-9} +(e^{-9} \times 9)+ \frac{e^{-9} \times 81}{2}$

= 0.00623

(b) Here, $\lambda = 9 \times 2$ = 18 because we have to find the probability for the next two hours and we are given in the question of per hour.

So, X ~ Poisson( $\lambda$ = 18)

Now, the probability that during the next two hours exactly 8 patients will be admitted is given by = P(X = 8)

P(X = 8) = $\frac{e^{-18} \times 18^{8} }{8!}$

= 0.00416

3 0

3 years ago