There is 0.02538502095915 Moles in 5 grams of gold.
Answer:
Explanation:
Pb(NO3)2(aq) + 2NaCl(aq) ==> PbCl2(s) + 2NaNO3(aq)
NO3- mixes with everything at beginning levels.
PbCl2 doesn't mix at all in water. It becomes a ppte, which means it is solid form. Your teacher might prefer using PbCl2(ppte). I think I'd ask to make sure.
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
Answer:
392 g
Explanation:
The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.
With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:
- Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
