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ch4aika [34]
3 years ago
7

List what type the following reactions are:

Chemistry
1 answer:
Ulleksa [173]3 years ago
7 0

Answer:

Number 6

Explanation:

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How do you get the electron configuration for an anion?
MissTica

Answer:

Anions electronic configuration is given by adding electrons.

4 0
2 years ago
What minimum volume of 0.200 m potassium iodide solution is required to completely precipitate all of the lead in 155.0 ml of a
Blababa [14]
First, we write the balanced equation for this reaction:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:

Moles = volume (in L) * molarity

We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:

M₁V₁ = 2M₂V₂

V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L


The volume required is 173.6 mL
5 0
3 years ago
Solid sodium azide (NaN3) produces solid sodium and nitrogen gas. How many grams of sodium azide are needed to yield a volume of
ch4aika [34]

Answer:

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P*V = n*R*T

In this case, the balanced reaction is:

2 NaN₃ → 2 Na + 3 N₂

You know the following about N₂:

  • P= 1.10 atm
  • V= 26.5 L
  • n=?
  • R=0.082057 \frac{atm*L}{mol*K}
  • T= 295 K

Replacing in the equation for ideal gas:

1.10 atm* 26.5 L= n* 0.082057 \frac{atm*L}{mol*K}*295 K

Solving:

n=\frac{1.10 atm*26.5 L}{0.082057 \frac{atm*L}{mol*K} *295K}

n= 1.2 moles

Now, the following rule of three can be applied: if 3 moles of N₂ are produced by stoichiometry of the reaction from 2 moles of NaN₃, 1.2 moles of N₂ are produced from how many moles of NaN₃?

moles of NaN_{3}=\frac{1.2 molesofN_{2} *2 molesofNaN_{3} }{3 molesofN_{2} }

moles of NaN₃= 0.8

Since the molar mass of sodium azide is 65.01 g / mol, then one last rule of three applies: if 1 mol has 65.01 grams of NaN₃, 0.8 mol how much mass does it have?

mass of NaN_{3} =\frac{0.8 mol*65.01 grams}{1 mol}

mass of NaN₃=52.008 grams

<u><em>52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.</em></u>

6 0
3 years ago
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Is the following detente true or false? Paramecia have two nuclei
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Paramecia have a micro nuclei and a macro nuclei.
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