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RoseWind [281]
3 years ago
12

A sample of a compound contains 60.0g C and 5.05 H it’s molar mass is 78.12g what is the compounds molecular formula

Chemistry
1 answer:
Svetach [21]3 years ago
6 0
The compound's molecular formula is C6H6
You might be interested in
When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation fo
Mashcka [7]

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

           KOH   +   BaCl₂    ⇒    KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               1                     K                      1

               1                     Ba                    1

               2                    Cl                     1  

                1                     H                    2

                1                     O                    2

The reaction is unbalanced

        2KOH   +   BaCl₂    ⇒   2KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               2                     K                     2

               1                     Ba                    1

               2                    Cl                     2  

               2                      H                    2

               2                     O                    2

Now, the reaction is balanced

7 0
3 years ago
Read 2 more answers
10.00 g of O2 reacts with 20.00 g NO Determine the amount of NO2, limiting reactant, and the excess reactant.
Nataliya [291]

Answer:

Limiting reactant: O₂

Excess reactant: NO

Amount of NO₂ produced: 28.75 g

Explanation:

The balanced equation for the reaction between O₂ and NO to produce NO₂ is the following:

O₂(g) + 2NO(g) → 2NO₂(g)

According to the equation, 1 mol of O₂ reacts with 2 moles of NO to produce 2 moles of NO₂.

We first convert the moles of each compound to mass by using the molecular weight (MW):

MW(O₂) = 16 g/mol x 2 = 32 g/mol

⇒ mass O₂ = 1 mol O₂ x 32 g/mol O₂ = 32 g

MW(NO) = 14 g/mol + 16 g/mol = 30 g/mol

⇒ mass NO = 2 mol NO x 30 g/mol NO = 60 g

MW(NO₂) = 14 g/mol + (2x 16 g/mol) = 46 g/mol

⇒ mass NO = 2 mol NO₂ x 46 g/mol NO₂ = 92 g

For the reactants, the stoichiometric ratio is 32 g O₂/60 g NO. Thus, the mass of O₂ required to completely react with 20.00 g of NO is:

mass of O₂ required = 20.00 g NO x 32 g O₂/60 g NO = 10.67 g O₂

We need 10.67 g of O₂ and we have only 10.00 g, so the limiting reactant is O₂. Thus, the excess reactant is NO.

With the limiting reactant, we calculate the amount of product produced (NO₂). For this, we consider the stoichiometric ratio 92 g NO₂/32 g O₂:

mass of NO₂ produced = 10.00 g O₂ x 92 g NO₂/32 g O₂ = 28.75 g NO₂

5 0
3 years ago
Rank the following compounds in order of increasing solubility in water. Items (4 items) (Drag and drop into the appropriate are
charle [14.2K]

Answer:

CaO < BaO < KCl <KI

Explanation:

Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy.  If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.

However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.

KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.

6 0
3 years ago
The neutralization of a 0.455 g sample of recrystallized aspirin required 38.6 mL of 0.100 M NaOH solution. An additional 25.0 m
Schach [20]

Answer:

E) Two of the above statements are true.

Explanation:

The options are:

A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. <em>TRUE. </em>Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.

B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. <em>FALSE. </em>As was explained, before the titration, the solution is pink.

C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. <em>TRUE. </em>Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.  

D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. <em>FALSE. </em>NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely

E) Two of the above statements are true. <em>TRUE</em>

<em></em>

Right option is:

<h3>E) Two of the above statements are true.</h3>
3 0
3 years ago
The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

Learn more about Gibbs free energy here:

brainly.com/question/13765848

#SPJ4

7 0
2 years ago
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