Multiple Choice:

According to the collision theory and model created to explain the collision theory, what two factors must be satisfied for a gi

storchak [24]

The answer is correct orientation and sufficient energy. Answer choice D

4 0

3 years ago

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For each property listed, identify the type of element it describes.

Juliette [100K]

Answer:

1.Very good electrical conductivity : Metals (Decreacing order of conductivity)

Silver > Copper > Gold > aluminium

2. Amphoteric : Metal elements

Beryllium , Aluminium , Zinc ,

3.Gaseous at room temperature: mostly Nobel gases elements and some non - metal elements.

Helium ,neon , argon , krypton , fluorine , Oxygen , nitrogen

4.Solid at room temperature: Mostly Metals (few non-metals, metalloid elements)

Metals (Sodium , potassium , calcium , gold are solid)

Non- metals(Carbon ,Boron )

Metalloids(antimony)

5. Brittle : non - metals (can't be rolled into wires)

Hydrogen , carbon , sulfur , phosphorus

Explanation:

6 0

3 years ago

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Which is a characteristic of mixtures?

siniylev [52]

Answer:

The correct answer is "They can be separated by physical processes"

Explanation:

The definition of Mixtures is the blending of two or more dissimilar substances.

Mixtures can be divided into those that are homogeneous or heterogeneous meaning that they can be distributed evenly or can't be distributed evenly.

6 0

3 years ago

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A force of 12.5 N is appiled to 10 kg mass

lina2011 [118]

To find the acceleration, use the formula: force= mass x acceleration. 12.5 N = 10 x Acceleration Acceleration = 12.5 / 10 Acceleration = 1.25 Hope this helps :)

6 0

4 years ago

You are given 25.00 mL of an acetic acid solution of unknown concentration. You find it requires 35.75 mL of a 0.1950 M NaOH sol

oee [108]

Answer:

0.2788 M

1.674 %(m/V)

Explanation:

Step 1: Write the balanced equation

NaOH + CH₃COOH → CH₃COONa + H₂O

Step 2: Calculate the reacting moles of NaOH

$0.03575 L \times \frac{0.1950mol}{L} = 6.971 \times 10^{-3} mol$

Step 3: Calculate the reacting moles of CH₃COOH

The molar ratio of NaOH to CH₃COOH is 1:1.

$6.971 \times 10^{-3} molNaOH \times \frac{1molCH_3COOH}{1molNaOH} = 6.971 \times 10^{-3} molCH_3COOH$

Step 4: Calculate the molarity of the acetic acid solution

$M = \frac{6.971 \times 10^{-3} mol}{0.02500L} =0.2788 M$

Step 5: Calculate the mass of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

$6.971 \times 10^{-3} mol \times \frac{60.05g}{mol} =0.4186 g$

Step 6: Calculate the percentage of acetic acid in the solution

$\frac{0.4186g}{25.00mL} \times 100\% = 1.674 \%(m/V)$

6 0

3 years ago

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