Answer:
Partial pressure Ne = 340 Torr
Option B
Explanation:
Gases contained in the vessel:
N₂, Ar, He, Ne
One of Dalton's law for gases determine this:
In a mixture of gases contained in a vessel, total pressure of the system must be the sum of partial pressure of each gas.
Total pressure = 1100 Torr
Let's replace:
Partial pressure N₂ + Partial pressure Ar + Partial pressure He + Partial pressure Ne = 1100 Torr
Partial pressure Ne = 1100 Torr - Partial pressure N₂ - Partial pressure Ar -Partial pressure He
Partial pressure Ne = 1100 Torr - 110 Torr - 250 Torr - 400 Torr
Partial pressure Ne = 340 Torr
Answer:
48 grams
Explanation:
The chemical equation for the reaction is the following:
2 H₂ + O₂ → 2 H₂O
That means that 2 moles of H₂ react with 1 mol of O₂ to produce 2 moles of H₂O. We convert the moles of oxygen (O₂) by using the molecular weight (MW) as follows:
MW(O₂) = 16 g/mol x 2 = 32 g/mol
mass of O₂ = 1 mol x 32 g/mol = 32 g
So, we have the following stoichiometric ratio: 32 g O₂/2 moles H₂. We have 3 moles of hydrogen (H₂), so we multiply the moles by the stoichiometric ratio to calculate how many grams are needed:
3 moles H₂ x 32 g O₂/2 moles H₂ = 48 g O₂
<em>Therefore, 48 grams of O₂ are needed to react with 3 moles of H₂.</em>
The water becomes a vapor. there are 2 ways condensation happens: either the air is cooled to its dew point or it becomes so saturated with water vapor that it cannot hold any more water.
Answer:
We need 78.9 mL of the 19.0 M NaOH solution
Explanation:
Step 1: Data given
Molarity of the original NaOH solution = 19.0 M
Molarity of the NaOH solution we want to prepare = 3.0 M
Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L
Step 2: Calculate volume of the 19.0 M NaOH solution needed
C1*V1 = C2*V2
⇒with C1 = the concentration of the original NaOH solution = 19.0 M
⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED
⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M
⇒with V2 = the volume of the NaOH solution we want to prepare = 500 mL = 0.500 L
19.0 M * V2 = 3.0 M * 0.500 L
V2 = (3.0 M * 0.500L) / 19.0 M
V2 = 0.0789 L
We need 0.0789 L
This is 0.0789 * 10^3 mL = 78.9 mL
We need 78.9 mL of the 19.0 M NaOH solution
Answer:
2. A
3.B
4.B
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