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Nataly [62]
3 years ago
7

List any two uses of Brass , Bronze , Sulphur , Iodine

Chemistry
1 answer:
NikAS [45]3 years ago
5 0

BRASS :It is easy to form into various shapes, a good conductor of heat, and generally resistant to corrosion from salt water. 1 pipes and 2 tubes, 3 screws, 4 cartridge casings for firearms.

BRONZE :for bearings because of its friction properties, and as 1 musical instruments ,2 and medals

Sulphur :1 making car batteries, 2 fertilizer

IODINE :1 Iodine regulates skin moisture levels and aids in the healing of cuts and scars through cellular regeneration. 2 Iodine also regulates the hormones responsible for acne breakouts.3 Treating thyroid cancer.

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Why is it important for scientists to review and repeat the work of other scientists?
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Scientists repeat experiments for reliability.  Experiments have to be repeated, since performing an experiment only once, does not prove a scientists theory on the experiment, which they develop by performing the experiment.  And then performing the experiment again or even many times to prove or disapprove their theories.  Btw, before an experiment begins, the scientist will make a hypothesis of what they believe will happen.  If proven correctly, they would then use those results they record throughout the experiment, from beginning to end to prove whether or not their hypothesis are correct or incorrect.  Click to let others know, how helpful is it


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So that they can prove the other scientists views wrong and develop a new theory in which there is more sense and credibility.  

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7 0
3 years ago
Read 2 more answers
A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
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The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

q_{released}=q_{absorbed}\\&#10;q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T

The given mass of calorimeter has been, m_{calorimeter}=1350\;\rm g

The specific heat of the calorimeter has been, c_{calorimeter}=5.82\;\rm J/g^\circ C

The change in temperature of the calorimeter has been, \Delta T=2.87^\circ \rm C

Substituting the values for heat released:

q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

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