Question

A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law you used to solve the problem.
1 point- Identify which of the Gas Laws you used to solve the problem.
3 points- Show your work on solving the problem.

PLEASE HELP IM SO LOST

Answer 1

Answer:

1.  Solved by Charles' Law

2. 621 L

Explanation:

Data Given:

Initial temperature T1=331 K

final Temperature T2= 376 K

initial volume V1 = 547 L

final volume V2 = ?

Solution:

This problem will be solved by Charles' Law equation at constant pressure

Charles' Law: It state that volume have direct relation with temperature at constant pressure.

               V1 / T1 = V2 / T2 . . . . . . . . (1)

put values in above equation

               547 L / 331 K = V2 / 376 K

Rearrange the above equation to calculate V2

            V2 = ( 547 L / 331 K) x 376 K

            V2 = ( 1.653 L . K) x 376 K

            V2 = 621 L

So the final volume = 621 L

So by increase of the temperature volume also increase according to Charles' law

Answer 2

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

    $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

 V₁ is the initial volume

 T₁ is the initial temperature

 V₂ is the final volume

 T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

   V₂ = $\frac{V_{1} }{T_{1} } x T_{2} = \frac{547}{331 } x 376$

 V₂ =  621.4L

learn more:

Boyle's law brainly.com/question/8928288

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