Ok, here we go. Pay attention. The formula for the arc length is
. That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is
(that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of
. Integrating that we have
from -1 to 2.
gives us
. Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly:
which simplifies to
. The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with
. And there you go!
Answer:
81
Step-by-step explanation:
i added it all
first one is C and second is D
Answer:
Equation of line best fits the scatter plot is y =
Step-by-step explanation:
Let the equation of line be y = mx + c
where m = slope of line and c is the intercept on y -axis
from the graph intercept on y-axis is 108
and the slope of line is given by m = where () and () is the points on line
let, points be (4,96) and (18,36)
on calculating this m = =
Therefore equation of line best fits the scatter plot is y =
Answer:
Last Choice / D
Step-by-step explanation:
you want to isolate v!
E = 1/2 m v^2
multiply both sides by 2
2E = mv^2
divide both sides by m
2E/m = v^2
square root both sides
v = ±
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